Math Problem Statement

What is the function f(n) = 6(2^n) and how does it behave as n increases?

Solution

The image shows the function f(n)=6(2n)f(n) = 6(2^n).

This function is an exponential function, where the output depends on nn, the exponent applied to the base 2, and then multiplied by 6. As nn increases, the function grows exponentially because of the factor 2n2^n.

For example:

  • When n=0n = 0, f(0)=6(20)=6(1)=6f(0) = 6(2^0) = 6(1) = 6.
  • When n=1n = 1, f(1)=6(21)=6(2)=12f(1) = 6(2^1) = 6(2) = 12.
  • When n=2n = 2, f(2)=6(22)=6(4)=24f(2) = 6(2^2) = 6(4) = 24.

Would you like further details or specific questions about this function? Here are 5 related questions for further exploration:

  1. What is the general behavior of exponential functions compared to linear or polynomial functions?
  2. How would you differentiate f(n)=6(2n)f(n) = 6(2^n) with respect to nn?
  3. What happens to f(n)f(n) as nn \to \infty?
  4. How can this function be applied in real-world contexts, such as population growth or computer science (e.g., binary systems)?
  5. Can you express f(n)f(n) in terms of logarithms for solving equations involving nn?

Tip: Exponential growth accelerates rapidly, so functions like 2n2^n grow much faster than polynomial functions as nn increases.

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Math Problem Analysis

Mathematical Concepts

Exponential Functions
Algebra

Formulas

f(n) = 6(2^n)

Theorems

Exponential Growth

Suitable Grade Level

Grades 9-12