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The problem asks how much money a company will make in 10 years if its current profits are decreasing by 53% per year. The current profit is given as \( 1.34958 \times 10^7 \) dollars per year.

This is an exponential decay problem, where the formula to calculate the profit after \( t \) years is:

\[
P(t) = P_0 (1 - r)^t
\]

Where:
- \( P(t) \) is the profit after \( t \) years.
- \( P_0 = 1.34958 \times 10^7 \) is the initial profit.
- \( r = 0.53 \) is the rate of decrease (53%).
- \( t = 10 \) is the number of years.

Let's calculate:

\[
P(10) = 1.34958 \times 10^7 \times (1 - 0.53)^{10}
\]
\[
P(10) = 1.34958 \times 10^7 \times (0.47)^{10}
\]

First, we calculate \( (0.47)^{10} \):

\[
0.47^{10} \approx 0.000340506
\]

Now multiply that by \( 1.34958 \times 10^7 \):

\[
P(10) \approx 1.34958 \times 10^7 \times 0.000340506
\]
\[
P(10) \approx 4590.23
\]

So, the company's profit 10 years from now will be approximately **4590.23 dollars**.

This value is closest to option 2: 4417.98.

Would you like more details on how the decay formula works or have any other questions? Here are 5 related questions you might find helpful:
1. How does the formula for exponential decay apply to other types of problems?
2. What happens if the rate of decrease changes over time?
3. How do you solve exponential growth problems instead of decay?
4. Can we calculate profits for any future time period?
5. How does compound interest differ from exponential decay?

**Tip**: When solving exponential decay problems, always make sure to subtract the rate of decay from 1 before raising it to the power of \( t \).

If a company's profits are currently 1.34958 × 10^7 dollars/year but are decreasing at 53%/year, how much money will the company make 10 years from now?

Learn how to solve an exponential decay problem where a company's profits are decreasing at a rate of 53% per year. Starting with a profit of 1.34958 × 10^7 dollars, we calculate the profit after 10 years using the exponential decay formula.

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