Math Problem Statement

is this true or not

Is this true or not?

Solution

The image shows the calculation of the expectation value E(x2)E(x^2), which is typically done for a normal distribution, where the probability density function (PDF) is given by f(x)=12πex2/2f(x) = \frac{1}{\sqrt{2\pi}} e^{-x^2 / 2}. Let's go through each step:

  1. First Line: E(x2)=x2f(x)dxE(x^2) = \int_{-\infty}^{\infty} x^2 f(x) \, dx

    • This is the definition of the expected value of x2x^2, where f(x)f(x) is the probability density function (presumably for a normal distribution).
  2. Second Line: E(x2)=x2ex2/2dxE(x^2) = \int_{-\infty}^{\infty} x^2 e^{-x^2 / 2} \, dx

    • The PDF f(x)f(x) is replaced with ex2/2e^{-x^2 / 2}, which implies a standard normal distribution (ignoring constants).
  3. Third Line: A substitution is made: u=x22u = \frac{x^2}{2}, which gives x2=2ux^2 = 2u and du=xdxdu = x dx.

    • The integral is transformed using this substitution, and the bounds change accordingly. This leads to: 0(2u)eudu\int_0^\infty (2u) e^{-u} du
  4. Fourth Line: Simplifies to: 40ueudu4 \int_0^\infty u e^{-u} du This is a standard Gamma function integral Γ(n)=0un1eudu\Gamma(n) = \int_0^\infty u^{n-1} e^{-u} du, with n=2n = 2.

  5. Final Line: The result of the Gamma function Γ(2)=1!=1\Gamma(2) = 1! = 1, so the integral becomes: 4×1=44 \times 1 = 4

Conclusion:

The steps are correct, and the result E(x2)=4E(x^2) = 4 is true, assuming the constants associated with the normal distribution (like 12π\frac{1}{\sqrt{2\pi}}) are omitted in the setup.

Let me know if you'd like more details on any of these steps!


Here are some related questions to expand your understanding:

  1. What is the role of the Gamma function in solving integrals?
  2. How would the result change if the normalization constant 12π\frac{1}{\sqrt{2\pi}} was included?
  3. Can you explain the method of substitution used in this problem?
  4. What is the expected value of x2x^2 for a non-standard normal distribution (with mean and variance)?
  5. How does this approach differ when calculating the variance Var(x)=E(x2)(E(x))2\text{Var}(x) = E(x^2) - (E(x))^2?

Tip: When performing substitutions in integrals, always remember to change the limits of integration to match the new variable of substitution.

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Math Problem Analysis

Mathematical Concepts

Probability and Statistics
Integration
Gamma Function
Expectation Value

Formulas

E(x^2) = ∫x^2 f(x) dx
f(x) = (1/√(2π)) e^(-x^2/2)
Γ(n) = ∫0^∞ u^(n-1) e^(-u) du

Theorems

Gamma Function
Substitution Method in Integration

Suitable Grade Level

University Level (Advanced Calculus/Probability Theory)