Let's expand the expression $(x + 5)(2x - 3)$.

We can use the distributive property (also known as the FOIL method) to multiply the two binomials.

$(x + 5)(2x - 3) = x(2x - 3) + 5(2x - 3)$

Now, distribute each term:

$x(2x - 3) = x \cdot 2x - x \cdot 3 = 2x^2 - 3x$ $5(2x - 3) = 5 \cdot 2x - 5 \cdot 3 = 10x - 15$

Now, combine all the terms:

$2x^2 - 3x + 10x - 15$

Combine the like terms $-3x$ and $10x$:

$2x^2 + 7x - 15$

So, the expanded form of $(x + 5)(2x - 3)$ is:

$2x^2 + 7x - 15$

Let me know if you'd like further details or have any questions!

Here are 5 related questions you might find interesting:

1. How do you factor a quadratic expression like $2x^2 + 7x - 15$?
2. What is the FOIL method, and how is it used for multiplying binomials?
3. How can you solve a quadratic equation like $2x^2 + 7x - 15 = 0$?
4. What happens if you have a negative sign inside a binomial, like $(x - 5)(2x + 3)$?
5. How do you recognize if an expression is a perfect square trinomial?

Tip: Always remember to combine like terms when expanding polynomials!