Math Problem Statement

f(b) = (b+6) (b-2)

Solution

Given the function f(b)=(b+6)(b2)f(b) = (b + 6)(b - 2), you can expand it to find a simplified expression.

Let's expand it:

f(b)=(b+6)(b2)f(b) = (b + 6)(b - 2)

Use the distributive property (also known as the FOIL method for binomials):

f(b)=bb+b(2)+6b+6(2)f(b) = b \cdot b + b \cdot (-2) + 6 \cdot b + 6 \cdot (-2)

Simplifying each term:

f(b)=b22b+6b12f(b) = b^2 - 2b + 6b - 12

Combine like terms:

f(b)=b2+4b12f(b) = b^2 + 4b - 12

So, the simplified form of the function is:

f(b)=b2+4b12f(b) = b^2 + 4b - 12

Would you like further details or have any questions?

Here are some related questions:

  1. How do you factorize a quadratic expression?
  2. What is the vertex form of a quadratic function?
  3. How do you find the roots of f(b)=b2+4b12f(b) = b^2 + 4b - 12?
  4. What is the significance of the discriminant in a quadratic equation?
  5. How does the graph of f(b)=b2+4b12f(b) = b^2 + 4b - 12 look?

Tip: When dealing with quadratic functions, always try to simplify the expression first to make further calculations easier.

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Math Problem Analysis

Mathematical Concepts

Algebra
Quadratic Functions
Polynomial Expansion

Formulas

Distributive Property
Quadratic equation in the form ax^2 + bx + c

Theorems

None specific; general algebraic manipulation

Suitable Grade Level

Grades 8-10