Math Problem Statement

Expand the brackets and then simplify 5n + 3(4 + 2n).

Solution

The problem in the image is:

Expand the brackets and simplify 5n+3(4+2n)5n + 3(4 + 2n).

Step 1: Expand the brackets

Distribute 33 across (4+2n)(4 + 2n): 3(4+2n)=34+32n=12+6n.3(4 + 2n) = 3 \cdot 4 + 3 \cdot 2n = 12 + 6n.

Step 2: Rewrite the expression

The expanded form becomes: 5n+12+6n.5n + 12 + 6n.

Step 3: Combine like terms

Combine 5n5n and 6n6n (the terms involving nn): 5n+6n=11n.5n + 6n = 11n. Now add the constant 1212: 11n+12.11n + 12.

Final Answer:

11n+1211n + 12

Let me know if you'd like a deeper explanation of any step!


Related Questions:

  1. How do you distribute terms over brackets in expressions like a(b+c)a(b + c)?
  2. Can you explain combining like terms with more examples?
  3. How would this process differ if there were subtraction in the brackets instead of addition?
  4. What happens if the brackets include more complex expressions, like (x2+3x)(x^2 + 3x)?
  5. How does this relate to solving equations involving brackets?

Tip:

Always simplify expressions step by step: expand brackets first, then combine like terms.

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Math Problem Analysis

Mathematical Concepts

Algebra
Expanding Brackets
Simplifying Expressions

Formulas

Distributive property: a(b + c) = ab + ac

Theorems

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Suitable Grade Level

Grades 6-8