To expand the expression \((6a - 5)(6a + 5)\), we can use the difference of squares formula, which is:

\[
(x - y)(x + y) = x^2 - y^2
\]

Here, \(x = 6a\) and \(y = 5\). Applying the formula:

\[
(6a - 5)(6a + 5) = (6a)^2 - (5)^2
\]

Now, calculate the squares:

\[
(6a)^2 = 36a^2 \quad \text{and} \quad 5^2 = 25
\]

So the expanded expression is:

\[
36a^2 - 25
\]

This is the fully expanded result.

Would you like further details on this expansion or any other questions?

Here are 5 related questions for further exploration:
1. How would you expand \((7a - 3)(7a + 3)\)?
2. What is the general formula for the difference of squares?
3. Can you factor the expression \(36a^2 - 25\) back into binomials?
4. How would you expand \((6a - 5)^2\)?
5. How do you factor quadratic expressions like \(x^2 - y^2\)?

**Tip:** The difference of squares formula is a quick way to expand or factor expressions that involve two terms with opposite signs.

Learn how to expand the expression (6a-5)(6a+5) using the difference of squares formula. This problem involves key algebraic concepts like polynomials and quadratic expansions, suitable for students in Grades 8-10. Explore related problems and explanations.

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