Math Problem Statement

limit of the function

limit of the function

Solution

The given function is:

f(x,y)=tan1(x+yx2+y2)f(x, y) = \tan^{-1} \left( \frac{|x| + |y|}{x^2 + y^2} \right)

To find the limit of this function as (x,y)(0,0)(x, y) \to (0, 0), let's analyze it.

Step 1: Understanding the Behavior Near the Origin

As (x,y)(0,0)(x, y) \to (0, 0), the function’s behavior is influenced by both the numerator x+y|x| + |y| and the denominator x2+y2x^2 + y^2.

Step 2: Polar Coordinates Substitution

Convert the function to polar coordinates where x=rcosθx = r\cos\theta and y=rsinθy = r\sin\theta. This transformation is useful as it simplifies expressions involving x2+y2\sqrt{x^2 + y^2}.

x+y=r(cosθ+sinθ)|x| + |y| = r(|\cos\theta| + |\sin\theta|)

x2+y2=r2x^2 + y^2 = r^2

So, the function becomes:

f(r,θ)=tan1(r(cosθ+sinθ)r2)=tan1(cosθ+sinθr)f(r, \theta) = \tan^{-1} \left( \frac{r(|\cos\theta| + |\sin\theta|)}{r^2} \right) = \tan^{-1} \left( \frac{|\cos\theta| + |\sin\theta|}{r} \right)

Step 3: Limit Analysis as r0r \to 0

As r0r \to 0, the term cosθ+sinθr\frac{|\cos\theta| + |\sin\theta|}{r} grows without bound because the denominator rr approaches zero while the numerator remains finite. Specifically, cosθ+sinθ|\cos\theta| + |\sin\theta| is always positive and bounded between 00 and 2\sqrt{2}.

Thus,

cosθ+sinθr as r0.\frac{|\cos\theta| + |\sin\theta|}{r} \to \infty \text{ as } r \to 0.

Step 4: Behavior of tan1(x)\tan^{-1}(x) as xx \to \infty

tan1(x)\tan^{-1}(x) approaches π2\frac{\pi}{2} as xx \to \infty.

Conclusion:

lim(x,y)(0,0)f(x,y)=π2.\lim_{(x, y) \to (0, 0)} f(x, y) = \frac{\pi}{2}.

Summary:

The limit of the function f(x,y)f(x, y) as (x,y)(0,0)(x, y) \to (0, 0) is π2\frac{\pi}{2}.


Would you like more details on this solution, or do you have any questions? Here are some related questions you might find interesting:

  1. How does the use of polar coordinates help in evaluating limits involving two variables?
  2. What are other techniques to evaluate limits that involve absolute values and powers?
  3. Can we use the Squeeze Theorem to find the limit of similar functions?
  4. How does the behavior of tan1(x)\tan^{-1}(x) affect limit evaluation?
  5. What are other examples of functions where the limit is influenced heavily by polar transformations?

Tip: Converting to polar coordinates can greatly simplify limit evaluation in two dimensions, especially when dealing with circular or symmetric behavior around the origin.

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Math Problem Analysis

Mathematical Concepts

Calculus
Limits
Trigonometry

Formulas

f(x, y) = tan^{-1} ( (|x| + |y|) / (x^2 + y^2) )

Theorems

Polar coordinates transformation
Behavior of arctangent as its argument approaches infinity

Suitable Grade Level

University Level (Calculus II or Multivariable Calculus)