Math Problem Statement

Show two ways of evaluating each expression: a) 6^2x6^3, b) 7^4x7^2, c) 9^5/9^3, d) (-7)^4/(-7)^3, e) (5^2)^3, f) (10^5)^2, g) (-8)^3(-8), and h) [(-1)^11]^9

Solution

To evaluate each expression in two different ways, we can either simplify using the properties of exponents or directly compute the values. Let's go through each problem.

a) 62×636^2 \times 6^3

Method 1: Use the product rule for exponents:

62×63=62+3=656^2 \times 6^3 = 6^{2+3} = 6^5 65=77766^5 = 7776

Method 2: Calculate each power separately and multiply:

62=36and63=2166^2 = 36 \quad \text{and} \quad 6^3 = 216 36×216=777636 \times 216 = 7776

b) 74×727^4 \times 7^2

Method 1: Use the product rule for exponents:

74×72=74+2=767^4 \times 7^2 = 7^{4+2} = 7^6 76=1176497^6 = 117649

Method 2: Calculate each power separately and multiply:

74=2401and72=497^4 = 2401 \quad \text{and} \quad 7^2 = 49 2401×49=1176492401 \times 49 = 117649

c) 9593\frac{9^5}{9^3}

Method 1: Use the quotient rule for exponents:

9593=953=92\frac{9^5}{9^3} = 9^{5-3} = 9^2 92=819^2 = 81

Method 2: Calculate each power separately and divide:

95=59049and93=7299^5 = 59049 \quad \text{and} \quad 9^3 = 729 59049729=81\frac{59049}{729} = 81

d) (7)4(7)3\frac{(-7)^4}{(-7)^3}

Method 1: Use the quotient rule for exponents:

(7)4(7)3=(7)43=(7)1=7\frac{(-7)^4}{(-7)^3} = (-7)^{4-3} = (-7)^1 = -7

Method 2: Calculate each power separately and divide:

(7)4=2401and(7)3=343(-7)^4 = 2401 \quad \text{and} \quad (-7)^3 = -343 2401343=7\frac{2401}{-343} = -7

e) (52)3(5^2)^3

Method 1: Use the power rule for exponents:

(52)3=52×3=56(5^2)^3 = 5^{2 \times 3} = 5^6 56=156255^6 = 15625

Method 2: Calculate the inner power first, then raise to the outer power:

52=255^2 = 25 253=1562525^3 = 15625

f) (105)2(10^5)^2

Method 1: Use the power rule for exponents:

(105)2=105×2=1010(10^5)^2 = 10^{5 \times 2} = 10^{10} 1010=1000000000010^{10} = 10000000000

Method 2: Calculate the inner power first, then raise to the outer power:

105=10000010^5 = 100000 1000002=10000000000100000^2 = 10000000000

g) (8)3×(8)(-8)^3 \times (-8)

Method 1: Combine the exponents:

(8)3×(8)=(8)3×(8)1=(8)3+1=(8)4(-8)^3 \times (-8) = (-8)^3 \times (-8)^1 = (-8)^{3+1} = (-8)^4 (8)4=4096(-8)^4 = 4096

Method 2: Calculate each power separately and multiply:

(8)3=512and(8)1=8(-8)^3 = -512 \quad \text{and} \quad (-8)^1 = -8 512×8=4096-512 \times -8 = 4096

h) [(1)11]9[(-1)^{11}]^9

Method 1: Simplify the inner expression first:

(1)11=1so(111)9=(1)9(-1)^{11} = -1 \quad \text{so} \quad (-1^{11})^9 = (-1)^9 (1)9=1(-1)^9 = -1

Method 2: Use the power rule for exponents:

[(1)11]9=(1)11×9=(1)99[(-1)^{11}]^9 = (-1)^{11 \times 9} = (-1)^{99} (1)99=1(-1)^{99} = -1


Do you want more details on any step or have any questions?

Here are 5 related questions to expand your understanding:

  1. What is the product rule of exponents, and why does it apply in these cases?
  2. How do we handle negative bases with exponents?
  3. What is the quotient rule for exponents, and how can it simplify expressions?
  4. How do you compute powers of large numbers without a calculator?
  5. What happens when the exponent of a negative number is even vs. odd?

Tip: Always check the sign when dealing with negative bases and odd or even exponents!

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Math Problem Analysis

Mathematical Concepts

Exponents
Algebra

Formulas

Product rule for exponents: a^m * a^n = a^(m+n)
Quotient rule for exponents: a^m / a^n = a^(m-n)
Power of a power rule: (a^m)^n = a^(m*n)

Theorems

Properties of exponents
Rules for handling negative bases with exponents

Suitable Grade Level

Grades 8-10