Math Problem Statement

Evaluate the integral.

2

(8ti − t3 j + 4t7 kdt

0

⟨16,4,128⟩    

Solution

It seems you're dealing with a vector-valued integral, where the integral is taken over a vector function. Let's break it down carefully:

You have the vector function:

F(t)=8tit3j+4t7k\mathbf{F}(t) = 8t \mathbf{i} - t^3 \mathbf{j} + 4t^7 \mathbf{k}

And the integral is expressed as:

02F(t)dt\int_0^2 \mathbf{F}(t) \, dt

This means you want to integrate the components of the vector function with respect to tt from 00 to 22.

Step 1: Split into components

We will handle the components of the vector function individually.

F(t)=8t,t3,4t7\mathbf{F}(t) = \langle 8t, -t^3, 4t^7 \rangle

So, the integral becomes:

028t,t3,4t7dt=028tdt,02t3dt,024t7dt\int_0^2 \langle 8t, -t^3, 4t^7 \rangle dt = \left\langle \int_0^2 8t \, dt, \int_0^2 -t^3 \, dt, \int_0^2 4t^7 \, dt \right\rangle

Step 2: Evaluate the individual integrals

  1. For the first component 8t8t: 028tdt=8[t22]02=8×42=16\int_0^2 8t \, dt = 8 \left[ \frac{t^2}{2} \right]_0^2 = 8 \times \frac{4}{2} = 16

  2. For the second component t3-t^3: 02t3dt=[t44]02=164=4\int_0^2 -t^3 \, dt = - \left[ \frac{t^4}{4} \right]_0^2 = - \frac{16}{4} = -4

  3. For the third component 4t74t^7: 024t7dt=4[t88]02=4×2568=128\int_0^2 4t^7 \, dt = 4 \left[ \frac{t^8}{8} \right]_0^2 = 4 \times \frac{256}{8} = 128

Step 3: Combine the results

Now, combining all the components, we get the result of the vector integral:

02F(t)dt=16,4,128\int_0^2 \mathbf{F}(t) \, dt = \langle 16, -4, 128 \rangle

Final Answer:

02F(t)dt=16,4,128\int_0^2 \mathbf{F}(t) \, dt = \langle 16, -4, 128 \rangle

Let me know if you need further clarification or any additional questions!


Here are some related questions you might find useful:

  1. What happens if the vector function changes form (e.g., a different exponent or coefficient)?
  2. How do we handle integrals of vector functions with more than one variable (multivariable)?
  3. What is the physical meaning of such integrals in a real-world context (e.g., work or force)?
  4. How can we handle integrals over more complex paths or curves?
  5. How do we interpret results of a vector-valued integral in terms of direction and magnitude?

Tip: Always ensure the components of the vector are handled individually and check the limits of integration to avoid mistakes!

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Math Problem Analysis

Mathematical Concepts

Vector Calculus
Definite Integrals
Vector-Valued Functions

Formulas

∫ a to b [f(t) dt] = F(b) - F(a)
Vector integral: ∫₀² ⟨f(t), g(t), h(t)⟩ dt = ⟨∫₀² f(t) dt, ∫₀² g(t) dt, ∫₀² h(t) dt⟩

Theorems

Fundamental Theorem of Calculus
Linearity of Integrals

Suitable Grade Level

Undergraduate Calculus