Math Problem Statement

Evaluate the expressions: (a) 4^(log4(8)), (b) 6^(log6(22)), (c) e^(ln(30)). Simplify your answers completely.

Solution

Let's analyze and solve the given problems:


(a) 4log4(8)4^{\log_4(8)}

Using the logarithmic property aloga(b)=ba^{\log_a(b)} = b, we have: 4log4(8)=84^{\log_4(8)} = 8


(b) 6log6(22)6^{\log_6(22)}

Similarly, applying the same property aloga(b)=ba^{\log_a(b)} = b: 6log6(22)=226^{\log_6(22)} = 22


(c) eln(30)e^{\ln(30)}

Using the exponential-logarithmic identity eln(a)=ae^{\ln(a)} = a: eln(30)=30e^{\ln(30)} = 30


Final Answers:

  1. (a): 88
  2. (b): 2222
  3. (c): 3030

Would you like me to explain the logarithmic property used in detail or provide additional examples? 😊


Related Questions:

  1. What is the general rule for simplifying aloga(b)a^{\log_a(b)}?
  2. How do the natural log ln\ln and base ee exponentials interact mathematically?
  3. How would the answers change if the logarithms had different bases (e.g., log2\log_2 instead of log4\log_4)?
  4. Can aloga(b)=ba^{\log_a(b)} = b be proven step-by-step?
  5. How can properties of logarithms be applied to expressions like loga(xy)\log_a(xy)?

Tip:

When simplifying expressions with logarithms and exponents, always check for the identity aloga(b)=ba^{\log_a(b)} = b and make sure the base matches!

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Math Problem Analysis

Mathematical Concepts

Logarithms
Exponential Functions
Simplification

Formulas

a^(log_a(b)) = b
e^(ln(a)) = a

Theorems

Exponential-Logarithmic Identity

Suitable Grade Level

Grades 9-12