The function given is $k(t) = 10t - 19$, and you are asked to find $k(-7)$.

To calculate $k(-7)$, substitute $t = -7$ into the equation:

$k(-7) = 10(-7) - 19$

$k(-7) = -70 - 19 = -89$

Thus, $k(-7) = -89$.

Would you like further clarification or more details on this?

Here are some related questions:

1. How do you solve for $k(t)$ if the function was quadratic instead of linear?
2. What happens to $k(t)$ as $t \to \infty$?
3. How do linear functions like $k(t) = 10t - 19$ graph on a coordinate plane?
4. How does changing the coefficient of $t$ affect the slope of the graph?
5. Can you explain how the constant term $-19$ affects the graph of the function?

Tip: In linear functions of the form $k(t) = at + b$, $a$ determines the slope, and $b$ determines where the graph crosses the y-axis (the intercept).