Math Problem Statement
Solution
To evaluate the given limit using L'Hôpital's Rule, let us proceed step by step.
The problem is:
Step 1: Check the indeterminate form
As , evaluate each term:
- , so .
- , so .
- The denominator .
Thus, the limit is of the form . This indicates a singularity, and L'Hôpital's Rule applies.
Step 2: Differentiate numerator and denominator
To apply L'Hôpital's Rule, differentiate the numerator and denominator with respect to .
- Numerator:
Differentiate term by term:
- For , rewrite as . Its derivative is:
- For , its derivative is:
Thus, the derivative of the numerator is:
- Denominator:
The derivative of the denominator is:
Step 3: Apply L'Hôpital's Rule
Now, apply L'Hôpital's Rule:
Substitute and :
Step 4: Evaluate the limit as
As :
Thus, the term , and the other term .
Hence, the overall limit is infinite:
Final Answer:
The limit diverges to infinity.
Do you want me to explain any step in more detail or clarify any concept?
Here are 5 related questions to deepen your understanding:
- What is L'Hôpital's Rule, and when can it be applied?
- How do you differentiate trigonometric functions like and ?
- What are common indeterminate forms in limits?
- How do you handle singularities in limits?
- How can you analyze the behavior of trigonometric functions near critical points like ?
Tip: Always verify that the original limit is in an indeterminate form before applying L'Hôpital's Rule.
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Math Problem Analysis
Mathematical Concepts
Limits
L'Hôpital's Rule
Trigonometric Functions
Formulas
L'Hôpital's Rule: \( \lim_{x \to c} \frac{f(x)}{g(x)} = \lim_{x \to c} \frac{f'(x)}{g'(x)} \) (if indeterminate form exists)
Derivative of \( \sec x \): \( \frac{d}{dx}[\sec x] = \sec x \tan x \)
Derivative of \( \sin x \): \( \frac{d}{dx}[\sin x] = \cos x \)
Theorems
L'Hôpital's Rule
Suitable Grade Level
Undergraduate Calculus
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