Math Problem Statement

Evaluate \( \int_{-3}^{0} \left(1 + \sqrt{9 - x^2}\right) \, dx \).

Solution

To solve the integral

30(1+9x2)dx\int_{-3}^{0} \left(1 + \sqrt{9 - x^2}\right) \, dx

we can break down the solution into manageable steps.

Step 1: Split the Integral

We can separate the integral into two parts:

30(1+9x2)dx=301dx+309x2dx\int_{-3}^{0} \left(1 + \sqrt{9 - x^2}\right) \, dx = \int_{-3}^{0} 1 \, dx + \int_{-3}^{0} \sqrt{9 - x^2} \, dx

So, we have:

  1. 301dx\int_{-3}^{0} 1 \, dx
  2. 309x2dx\int_{-3}^{0} \sqrt{9 - x^2} \, dx

Step 2: Evaluate the First Integral

The first integral, 301dx\int_{-3}^{0} 1 \, dx, is straightforward:

301dx=[x]30=0(3)=3\int_{-3}^{0} 1 \, dx = \left[ x \right]_{-3}^{0} = 0 - (-3) = 3

Step 3: Evaluate the Second Integral

The second integral, 309x2dx\int_{-3}^{0} \sqrt{9 - x^2} \, dx, resembles the formula for the area of a semicircle. The function 9x2\sqrt{9 - x^2} represents the upper half of a circle with radius 33 (since 9=329 = 3^2).

The area of a semicircle of radius 33 is given by 12πr2\frac{1}{2} \pi r^2. So, for this part:

339x2dx=12π32=9π2\int_{-3}^{3} \sqrt{9 - x^2} \, dx = \frac{1}{2} \pi \cdot 3^2 = \frac{9\pi}{2}

However, since our integral is from 3-3 to 00 (covering only half of the semicircle), we take half of 9π2\frac{9\pi}{2}:

309x2dx=9π4\int_{-3}^{0} \sqrt{9 - x^2} \, dx = \frac{9\pi}{4}

Step 4: Combine the Results

Now, we add the two parts together:

30(1+9x2)dx=3+9π4\int_{-3}^{0} \left(1 + \sqrt{9 - x^2}\right) \, dx = 3 + \frac{9\pi}{4}

Final Answer

30(1+9x2)dx=3+9π4\int_{-3}^{0} \left(1 + \sqrt{9 - x^2}\right) \, dx = 3 + \frac{9\pi}{4}

Would you like more details on any step, or do you have any questions?


  1. How would this change if the integral limits were from 3-3 to 33?
  2. What is the geometrical interpretation of the term 9x2\sqrt{9 - x^2} in this integral?
  3. How would the approach differ if the term under the square root were not a perfect square, such as 8x2\sqrt{8 - x^2}?
  4. Can we apply substitution techniques to evaluate integrals of this form? If so, which ones?
  5. How would the solution change if the integrand were 19x21 - \sqrt{9 - x^2} instead?

Tip: For integrals involving a2x2\sqrt{a^2 - x^2}, consider the geometric properties of circles or trigonometric substitution methods.

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Math Problem Analysis

Mathematical Concepts

Integral Calculus
Geometric Interpretation of Integrals
Area of a Semicircle

Formulas

\( \int_{a}^{b} f(x) \, dx = F(b) - F(a) \)
Area of a semicircle = \( \frac{1}{2} \pi r^2 \)

Theorems

Definite Integral
Area Interpretation of Integrals

Suitable Grade Level

Undergraduate Calculus