To evaluate the definite integral $\int_{0}^{\pi} 2 \sin(x) \, dx$, follow these steps:

1. Find the antiderivative: The antiderivative of $2 \sin(x)$ is $-2 \cos(x)$.

2. Evaluate the definite integral using the limits: $\left. -2 \cos(x) \right|_{0}^{\pi} = -2 \cos(\pi) - (-2 \cos(0))$

3. Calculate the values:

   • $\cos(\pi) = -1$
   • $\cos(0) = 1$

   Substituting these values in: $-2(-1) - (-2 \times 1) = 2 - (-2) = 2 + 2 = 4$

So, the value of the definite integral is $4$.