Math Problem Statement

f(x) = x2^2 + 2 from x = 1 to x = 2.

Incorrect: Your answer is incorrect.

Solution

It looks like you're evaluating the function f(x)=x22+2f(x) = x \cdot 2^2 + 2 from x=1x = 1 to x=2x = 2.

Steps:

  1. Rewrite the function:
    f(x)=x22+2=x4+2=4x+2f(x) = x \cdot 2^2 + 2 = x \cdot 4 + 2 = 4x + 2

  2. Evaluate at x=1x = 1: f(1)=4(1)+2=4+2=6f(1) = 4(1) + 2 = 4 + 2 = 6

  3. Evaluate at x=2x = 2: f(2)=4(2)+2=8+2=10f(2) = 4(2) + 2 = 8 + 2 = 10

Therefore:

  • f(1)=6f(1) = 6
  • f(2)=10f(2) = 10

If you'd like further clarifications or details on the function evaluation, feel free to ask!

Related Questions:

  1. How would the function change if the coefficient of 2 was different?
  2. What is the general form of linear functions like f(x)=4x+2f(x) = 4x + 2?
  3. How would the result change if the interval were from x=0x = 0 to x=2x = 2?
  4. Can you calculate the average rate of change of f(x)f(x) over the interval [1,2][1, 2]?
  5. How would f(x)f(x) behave for negative values of xx?

Tip: Always simplify the constants before evaluating a function to avoid errors.

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Math Problem Analysis

Mathematical Concepts

Algebra
Linear Functions

Formulas

f(x) = 4x + 2

Theorems

Linear equation evaluation

Suitable Grade Level

Grades 6-8