Math Problem Statement

Evaluate a(b^2*cd^2) if a = –1, b = 2, c = –3, and d = 4.

Solution

We are given the expression a(b2cd2)a(b^2 \cdot c \cdot d^2) and the values:

  • a=1a = -1
  • b=2b = 2
  • c=3c = -3
  • d=4d = 4

Step-by-step Solution:

  1. Substitute the values into the expression: a(b2cd2)=1(22(3)42)a(b^2 \cdot c \cdot d^2) = -1 \cdot (2^2 \cdot (-3) \cdot 4^2)

  2. Evaluate b2b^2: b2=22=4b^2 = 2^2 = 4

  3. Evaluate d2d^2: d2=42=16d^2 = 4^2 = 16

  4. Multiply b2b^2, cc, and d2d^2: 4(3)16=1216=1924 \cdot (-3) \cdot 16 = -12 \cdot 16 = -192

  5. Multiply the result by aa: 1(192)=192-1 \cdot (-192) = 192

Final Answer:

192\boxed{192}

Let me know if you'd like a detailed explanation of any step!


Related Questions:

  1. How does changing bb to 2-2 affect the result?
  2. What happens if c=0c = 0? Does the answer change?
  3. How can we generalize this process for any values of a,b,c,da, b, c, d?
  4. What is the importance of exponents in simplifying such expressions?
  5. Can we solve a similar expression with fractional values for bb and dd?

Tip: Always handle negative signs carefully in multiplication, especially when working with powers!

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Math Problem Analysis

Mathematical Concepts

Exponents
Multiplication of Integers
Substitution

Formulas

a(b^2 * c * d^2)

Theorems

Properties of Exponents

Suitable Grade Level

Grades 6-8