To evaluate the given integral:

\[
\int_{0}^{\pi} \int_{0}^{\pi^2} \cos\left(\frac{x}{y}\right) \, dx \, dy
\]

we will first evaluate the inner integral with respect to \( x \), and then the outer integral with respect to \( y \).

### Step 1: Evaluate the inner integral
The inner integral is:

\[
\int_{0}^{\pi^2} \cos\left(\frac{x}{y}\right) \, dx
\]

Let \( u = \frac{x}{y} \). Then \( du = \frac{dx}{y} \), or \( dx = y \, du \). The limits for \( u \) will be from \( 0 \) to \( \frac{\pi^2}{y} \):

\[
\int_{0}^{\pi^2} \cos\left(\frac{x}{y}\right) \, dx = \int_{0}^{\pi^2/y} \cos(u) \, y \, du = y \int_{0}^{\pi^2/y} \cos(u) \, du
\]

We know that:

\[
\int \cos(u) \, du = \sin(u)
\]

Thus:

\[
y \int_{0}^{\pi^2/y} \cos(u) \, du = y \left[ \sin(u) \right]_0^{\pi^2/y} = y \left( \sin\left(\frac{\pi^2}{y}\right) - \sin(0) \right) = y \sin\left(\frac{\pi^2}{y}\right)
\]

So, the inner integral evaluates to:

\[
\int_{0}^{\pi^2} \cos\left(\frac{x}{y}\right) \, dx = y \sin\left(\frac{\pi^2}{y}\right)
\]

### Step 2: Evaluate the outer integral
Now we integrate the result with respect to \( y \):

\[
\int_{0}^{\pi} y \sin\left(\frac{\pi^2}{y}\right) \, dy
\]

This integral can be solved by a substitution. Let \( v = \frac{\pi^2}{y} \), then \( dv = -\frac{\pi^2}{y^2} \, dy \), or \( dy = -\frac{y^2}{\pi^2} \, dv \).

When \( y = 0 \), \( v \to \infty \), and when \( y = \pi \), \( v = \frac{\pi^2}{\pi} = \pi \).

Substituting these into the integral:

\[
\int_{0}^{\pi} y \sin\left(\frac{\pi^2}{y}\right) \, dy = \int_{\infty}^{\pi} \left(-\frac{\pi^4}{v^2} \sin(v)\right) dv
\]

Changing the limits to be from low to high:

\[
\int_{\pi}^{\infty} \frac{\pi^4}{v^2} \sin(v) \, dv
\]

This integral does not converge because \(\sin(v)\) oscillates indefinitely and the factor \(\frac{1}{v^2}\) is not sufficient to ensure convergence as \(v\) approaches infinity.

Hence, the original integral is divergent.

Would you like any details or have any questions?

Here are 8 related questions to expand on this topic:
1. How can we determine if an integral is convergent or divergent?
2. Can you explain the process of substitution in definite integrals?
3. What is the significance of changing the order of integration in double integrals?
4. How does the behavior of trigonometric functions at infinity affect the convergence of integrals?
5. What are some techniques to evaluate improper integrals?
6. How does one apply integration by parts to solve more complex integrals?
7. Can you solve a similar problem with a different integrand, like \(\cos(x \cdot y)\)?
8. How do the limits of integration influence the outcome of the double integral?

**Tip:** When evaluating integrals involving trigonometric functions over infinite limits, carefully check for convergence by considering the behavior of the integrand at the boundaries.

Learn how to evaluate the double integral ∫(π^2→0)∫ cos(x/y)dxdy step-by-step. This problem covers double integrals with trigonometric functions and examines convergence issues in improper integrals. Suitable for advanced mathematics enthusiasts.

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