Math Problem Statement

Evaluate _8C_4 and _9P_3.

Solution

The image asks to evaluate two expressions involving combinations and permutations:

  1. 8C4_8C_4 (combinations)
  2. 9P3_9P_3 (permutations)

1. Evaluating 8C4_8C_4:

The combination formula is given by: 8C4=8!4!(84)!=8!4!4!_8C_4 = \frac{8!}{4!(8 - 4)!} = \frac{8!}{4!4!} Simplifying this: 8C4=8×7×6×54×3×2×1=70_8C_4 = \frac{8 \times 7 \times 6 \times 5}{4 \times 3 \times 2 \times 1} = 70

2. Evaluating 9P3_9P_3:

The permutation formula is given by: 9P3=9!(93)!=9!6!_9P_3 = \frac{9!}{(9 - 3)!} = \frac{9!}{6!} Simplifying this: 9P3=9×8×7=504_9P_3 = 9 \times 8 \times 7 = 504

Final Answers:

  • 8C4=70_8C_4 = 70
  • 9P3=504_9P_3 = 504

Would you like any further clarification or details?


Here are 5 questions to expand your understanding:

  1. What is the difference between a combination and a permutation?
  2. How would 9C3_9C_3 differ from 9P3_9P_3 in terms of formula and result?
  3. How does the factorial function play a role in these formulas?
  4. In what types of problems would you use permutations instead of combinations?
  5. What happens to the values of permutations and combinations if the numbers are equal (e.g., 5C5_5C_5 or 5P5_5P_5)?

Tip: Always remember that order matters in permutations but not in combinations!

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Math Problem Analysis

Mathematical Concepts

Combinatorics
Combinations
Permutations
Factorial

Formulas

Combination formula: nCr = n! / (r!(n - r)!)
Permutation formula: nPr = n! / (n - r)!

Theorems

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Suitable Grade Level

Grades 9-12