To solve the expression $6x - y$, we first determine the values of $x$ and $y$ from the equations:

1. Given equations:

   • $3x = 3$
   • $2y = 2$

2. Solve for $x$: $3x = 3 \quad \Rightarrow \quad x = \frac{3}{3} = 1$

3. Solve for $y$: $2y = 2 \quad \Rightarrow \quad y = \frac{2}{2} = 1$

4. Substitute $x = 1$ and $y = 1$ into $6x - y$: $6x - y = 6(1) - 1 = 6 - 1 = 5$

Final Answer:

$\boxed{5}$

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Related Questions:

1. How do you solve linear equations with more variables?
2. What happens if $x$ and $y$ have fractional or negative values?
3. How would the result change if the coefficients in $6x - y$ were altered?
4. Can you graph $6x - y$ to visualize the result?
5. What is the significance of expressions in algebraic equations?

Tip:

Always substitute values step by step to avoid calculation errors!