The problem asks about estimating the side length of each square when a rectangle, with twice the length as its width, has an area of 94 square units. Let’s walk through the question step-by-step.

Analysis:

1. Area of the Rectangle:
   $A = 94 \, \text{square units}$.

2. Rectangle Properties:
   The length $L$ is twice the width $W$.
   So, $L = 2W$.

3. Finding the dimensions:
   Since the area of a rectangle is given by $A = L \times W$, substituting $L = 2W$: $94 = 2W \times W = 2W^2.$ Divide both sides by 2: $W^2 = \frac{94}{2} = 47.$ Now, take the square root of both sides to find $W$: $W = \sqrt{47}.$

4. Estimating the side length of each square:
   Since the question asks for the side length of each square (which is $\sqrt{47}$), the correct answer is B. Estimate $\sqrt{47}$.

Solution to the Remaining Part:

• Width (W):
  $W = \sqrt{47} \approx 6.9$ units.

• Length (L):
  $L = 2W = 2 \times 6.9 \approx 13.8$ units.

So, the rectangle is approximately 13.8 units long and 6.9 units wide.

Do you need any further clarification?

5 Related Questions:

1. How do you estimate square roots like $\sqrt{47}$ without a calculator?
2. What happens if the rectangle’s length is three times the width instead?
3. How does knowing the area help us determine the shape's dimensions?
4. How would the solution change if the area were 100 square units?
5. What is the geometric significance of dividing a rectangle into squares?

Tip:

When given a problem with relationships between dimensions (like length being twice the width), translating the relationships into algebraic expressions is a crucial first step.