Math Problem Statement

Complete the equivalent ratio tables by filling in the missing values based on the given ratios.

Solution

The worksheetIt looks like you've uploaded a worksheet on equivalent ratio deals tables. Let me break with down the approach for solving these ** types of problems.

To find the missingEquivalent values in the ratio tables Ratio Tables,** you'll. want Let's solve the to given problems determine the constant rate step by between the step values. I'll in each provide row the. solutions This for rate will the empty cells in allow you each to multiply or table divide to:


fill 1 in.

The given the ratio missing is values.

For example:

  1. **Row 11:The:tableshowsa3setof1 **1: The : table shows a3 set of. numbers Multiply starting the with first 1 row, values by3 , 34 to, 5. get You the second can calculate row the constant ratio (or:
  • 3multiplier3 multiplier bytimes 2 dividing = 6 )
  • the 3second×column3(=3)93 second \times column3 ( =3 )9
  • bythefirst3column×4=12by the first3 column \times 4 = 12 (1-), which gives ( a rate of 33. Apply this \times rate to5 = the other columns,15 \ multiplying)

each value by** Completed3 Table**.

: Would| you like me to help 1 | you2 | solve each table3 step |-by-step or4 address | 5 specific rows? | Please let me know how you'd like to proceed!

Additionally, here are some related questions that could expand your understanding of ratios:

  1. How do you find the ratio between two given numbers?
  2. What are some real-world scenarios where equivalent ratios are used?
  3. How can you check if a given table represents equivalent ratios|?
  4. What happens if the values in a ratio table don't maintain a--- constant|---|--- rate|? ---|---| | 3 | 65 |. 9 | 12 | 15 |

How---

do### 2. The you given ratio is ( use2 cross :-multip lication to5 solve ratio \ problems?

). MultiplyTip the first row values by: 5 When/ dealing with2 ratio to get tables, the always ensure second that the relationship row:

  • between ( the numbers remains consistent 5 \ (timesconstant rate2 = ) across10 each \ row or) column.- 5×6=305 \times 6 = 30

Completed Table:

21214
51535

Solutions Continued:


3.

The given ratio is 3:73 : 7. Multiply the first row values by 73\frac{7}{3}:

  • 15÷3=515 \div 3 = 5, so 5×7=355 \times 7 = 35
  • ( 21 \div...fixable: rewriteLet’s continue solving the ratio tables step-by-step.

2. (Completed earlier)

21214
51535

3.

The given ratio is 3:73 : 7. To find the missing values, multiply each value in the first row by 73\frac{7}{3}:

  • 15÷3=515 \div 3 = 5, so 5×7=355 \times 7 = 35
  • 21÷3=721 \div 3 = 7, so 7×7=497 \times 7 = 49

Completed Table:

31521
73549

4.

The given ratio is 6:76 : 7. Multiply each value in the first row by 76\frac{7}{6}:

  • 12÷6=212 \div 6 = 2, so 2×7=142 \times 7 = 14
  • 30÷6=530 \div 6 = 5, so 5×7=355 \times 7 = 35
  • 42÷6=742 \div 6 = 7, so 7×7=497 \times 7 = 49

Completed Table:

6123042
7143549

5.

The given ratio is 4:104 : 10. Multiply the first row values by 104=2.5\frac{10}{4} = 2.5:

  • 16÷4=416 \div 4 = 4, so 4×10=404 \times 10 = 40
  • 24÷4=624 \div 4 = 6, so 6×10=606 \times 10 = 60

Completed Table:

41624
104060

Let me know if you'd like me to proceed with the rest! Alternatively, I can provide a tip for solving equivalent ratios and additional follow-up questions.

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Math Problem Analysis

Mathematical Concepts

Ratios
Proportional Relationships
Multiplication
Division

Formulas

Missing value = (Known value in row/column) × Constant ratio

Theorems

Proportionality Theorem

Suitable Grade Level

Grades 5-6