To find the equation of a line, we can use the point-slope form of the equation of a line, which is given by:

$y - y_1 = m(x - x_1)$

Where:

• $m$ is the slope of the line,
• $(x_1, y_1)$ is a point on the line.

You are given:

• The slope $m = 4$,
• The point $(x_1, y_1) = (1, 4)$.

Substitute these values into the point-slope formula:

$y - 4 = 4(x - 1)$

Now, simplify the equation:

$y - 4 = 4x - 4$

Add 4 to both sides:

$y = 4x$

So, the equation of the line is:

$y = 4x$

Would you like more details or have any questions on this? Here are some related questions for further practice:

1. How do you convert the equation of the line from point-slope form to slope-intercept form?
2. What is the equation of a line with a slope of 4 that passes through the point (0, 0)?
3. How do you find the slope of a line if you are given two points, for example, (1, 4) and (3, 8)?
4. How do you determine if two lines are parallel or perpendicular based on their slopes?
5. Can you find the equation of a line passing through (2, 3) with a slope of -2?

Tip: Always double-check that you are using the correct form of the line equation depending on what information is provided (point-slope, slope-intercept, etc.).