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The problem asks to write the equation of a line in **slope-intercept form**, which is \( y = mx + b \), where:

- \( m \) is the slope
- \( b \) is the y-intercept

We are given:
- Slope \( m = -\frac{5}{4} \)
- A point on the line \( (4, -3) \)

### Step-by-step process:

1. **Substitute the point (4, -3) and the slope into the slope-intercept form** to find \( b \):
   \[
   y = mx + b
   \]
   Using \( x = 4 \), \( y = -3 \), and \( m = -\frac{5}{4} \):
   \[
   -3 = -\frac{5}{4}(4) + b
   \]
   
2. **Solve for \( b \)**:
   \[
   -3 = -5 + b
   \]
   \[
   b = -3 + 5 = 2
   \]

3. **Write the final equation**:
   \[
   y = -\frac{5}{4}x + 2
   \]

The equation of the line is \( y = -\frac{5}{4}x + 2 \).

Would you like more details or have any questions?

Here are 5 related questions:
1. How do you calculate the slope of a line between two points?
2. What is the general form of a linear equation, and how is it different from slope-intercept form?
3. How can you graph a line using its slope and y-intercept?
4. Can you convert this slope-intercept form to standard form?
5. How do you find the equation of a line parallel or perpendicular to this one?

**Tip:** When given a point and slope, always substitute into the slope-intercept form to easily find the equation of the line.

A line passes through the point (4, -3) and has a slope of -5/4. Write an equation in slope-intercept form for this line.

Learn how to write the equation of a line in slope-intercept form given a point (4, -3) and a slope of -5/4. This problem covers key concepts of algebra, including using the slope-intercept form and finding the y-intercept.

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