To find the equation of a line parallel to $y = -6$ that passes through the point $(-2, -5)$, we can analyze the form of the given line and apply parallel line properties.

1. The line $y = -6$ is a horizontal line, where every point on the line has $y$-coordinate $-6$. This means the slope of the line is zero (since it does not change in the $y$-direction).

2. A line parallel to $y = -6$ will also be horizontal, maintaining a slope of zero.

3. Since the line must pass through the point $(-2, -5)$, its $y$-coordinate must be $-5$.

Thus, the equation of the line parallel to $y = -6$ through the point $(-2, -5)$ is: $y = -5$

This line is horizontal, passing through all points where $y = -5$.

Would you like more details on horizontal and vertical lines, or do you have any questions?

Here are some related questions for further exploration:

1. How do you find the equation of a line perpendicular to $y = -6$?
2. What is the equation of a line parallel to $x = -3$ through a given point?
3. How do you find the slope of a line given two points on the line?
4. What is the distance between the lines $y = -6$ and $y = -5$?
5. How can we find the intersection of a horizontal and a vertical line?

Tip: For any horizontal line, the equation will always be $y = \text{constant}$, where the constant is the $y$-coordinate of any point on the line.