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To solve this problem, we need to write the equation of a line in *point-slope form*. 

The *point-slope form* of a linear equation is given by:

\[
y - y_1 = m(x - x_1)
\]

Where:
- \( m \) is the slope of the line,
- \( (x_1, y_1) \) is a point on the line.

### Given:
- The slope \( m = 7 \),
- The point \( (x_1, y_1) = (8, 3) \).

Substitute these values into the point-slope equation:

\[
y - 3 = 7(x - 8)
\]

This is the equation of the line in point-slope form.

Do you have any questions or would you like further details? Here are some related questions you could explore:

1. How can this point-slope form be converted to slope-intercept form?
2. What does the graph of this line look like?
3. Can the point-slope form be used with any other points on the same line?
4. How does the slope affect the steepness of the line?
5. What is the equation of a line perpendicular to this one passing through the same point?

**Tip:** Point-slope form is especially useful when you know a point on the line and the slope, but not necessarily the y-intercept.

A line that includes the point (8, 3) has a slope of 7. What is its equation in point-slope form?

Solve the problem of finding the equation of a line that passes through the point (8, 3) with a slope of 7. This problem uses the point-slope form equation y - y1 = m(x - x1) and is suitable for students in Grades 8-10.

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