Math Problem Statement

The Acme Company manufactures widgets. The distribution of widget weights is bell-shaped. The widget weights have a mean of 43 ounces and a standard deviation of 6 ounces.

Use the Empirical Rule.

Suggestion: sketch the distribution in order to answer these questions.

a) 99.7% of the widget weights lie between and

Solution

The Empirical Rule states that for a normal distribution:

  • 68% of data falls within 1 standard deviation of the mean.
  • 95% of data falls within 2 standard deviations of the mean.
  • 99.7% of data falls within 3 standard deviations of the mean.

Given that the mean is 4343 ounces and the standard deviation is 66 ounces:

To find the range where 99.7% of the weights lie:

We need to calculate 3 standard deviations above and below the mean:

  • Lower Bound: 433×6=4318=2543 - 3 \times 6 = 43 - 18 = 25 ounces
  • Upper Bound: 43+3×6=43+18=6143 + 3 \times 6 = 43 + 18 = 61 ounces

Answer:

99.7% of the widget weights lie between 25 ounces and 61 ounces.

Would you like a detailed explanation on how this applies to real-world data analysis or any other questions on this topic?

Here are 5 related questions to further explore this topic:

  1. What range would contain 95% of the widget weights?
  2. How would you determine the percentage of widgets that weigh more than 49 ounces?
  3. What is the probability of a widget weighing between 37 and 49 ounces?
  4. How does the Empirical Rule relate to the concept of z-scores?
  5. How would outliers affect the distribution in a real-world scenario?

Tip: The Empirical Rule is only applicable to distributions that are approximately normal (bell-shaped).

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Math Problem Analysis

Mathematical Concepts

Statistics
Normal Distribution
Empirical Rule

Formulas

Empirical Rule (68-95-99.7 rule)
Range for 99.7% = Mean ± 3 * Standard Deviation

Theorems

Empirical Rule (for normal distributions)

Suitable Grade Level

Grades 10-12