x²/8 +y²/4 =1 find ellipse properties and graph

Here is the graph of the ellipse represented by the equation \(\frac{x^2}{8} + \frac{y^2}{4} = 1\), with the foci marked at \((\pm 2, 0)\). The ellipse is wider along the x-axis due to the larger value of the semi-major axis.

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Here are some related questions for further exploration:
1. How does changing the values of \(a^2\) and \(b^2\) affect the shape of an ellipse?
2. What happens if \(a = b\) in an ellipse equation?
3. Can you explain how eccentricity impacts the shape of the ellipse?
4. How do you calculate the area of an ellipse?
5. What are the properties of an ellipse when the foci coincide?

**Tip:** The distance between the foci and the center defines how "stretched" an ellipse is. The greater this distance, the more elongated the ellipse.

x²/8 + y²/4 = 1 find ellipse properties and graph

Discover the properties and graph of the ellipse given by the equation x²/8 + y²/4 = 1. Learn how to find the semi-major axis, semi-minor axis, and foci, with detailed explanations suitable for high school students studying conic sections and coordinate geometry.

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