https://file.aiquickdraw.com/mathbot/file/1726044170983tab06vch.jpg

Let's go through the questions in the image step by step:

### 1. Fill in the table (8 marks):
The table requires you to fill in the missing **symbols** and **SI units** for various quantities. Here's the completed table:

| QUANTITY     | SYMBOL | SI UNIT  |
|--------------|--------|----------|
| 1. Resistance | R      | Ohm (Ω)  |
| 2. Voltage    | V      | Volt (V) |
| 3. Energy     | E      | Joule (J)|
| 4. Power      | P      | Watt (W) |
| 5. Conductance| G      | Siemens (S) |
| 6. Charge     | Q      | Coulomb (C)|
| 7. Capacitance| C      | Farad (F) |

### 2. Find the conductance of the circuit shown in the figure, given \(R_1\), \(R_2\), \(R_3\). (3 marks)
- Conductance \(G\) is the reciprocal of resistance.
  
  \[
  G = \frac{1}{R_{\text{total}}}
  \]
  For a parallel circuit, the total resistance \(R_{\text{total}}\) can be calculated using:
  
  \[
  \frac{1}{R_{\text{total}}} = \frac{1}{R_1} + \frac{1}{R_2} + \frac{1}{R_3}
  \]
  Once you calculate \(R_{\text{total}}\), use the formula for conductance:
  
  \[
  G = \frac{1}{R_{\text{total}}}
  \]

### 3. State Ohm’s Law (2 marks):
Ohm's Law states that the current (\(I\)) flowing through a conductor between two points is directly proportional to the voltage (\(V\)) across the two points and inversely proportional to the resistance (\(R\)).
  
  \[
  V = IR
  \]

### 4. Find the value of current in Figure 2 (3 marks):
Using Ohm's Law:

\[
I = \frac{V}{R}
\]
In Figure 2, the voltage \(V = 12V\) and the resistance \(R = 600 \Omega\).

\[
I = \frac{12}{600} = 0.02 \, \text{A} \, \text{or} \, 20 \, \text{mA}
\]

### 5. Show that the electrical power is determined using (4 marks):
(i) \( P = \frac{V^2}{R} \)
- From Ohm's law \(V = IR\), we know that power \(P = VI\). Substituting \(I = \frac{V}{R}\):
  
  \[
  P = V \times \frac{V}{R} = \frac{V^2}{R}
  \]

(ii) \( P = I^2R \)
- Again using \(P = VI\), substitute \(V = IR\):

  \[
  P = I \times (IR) = I^2R
  \]

### 6. Explain why electrical appliances are connected in parallel (2 marks):
- Electrical appliances are connected in parallel so that each appliance operates independently. In parallel circuits, the voltage across each appliance is the same, and one appliance can be switched off without affecting the others. Additionally, the total current in the circuit is divided among the appliances, making it safer for operation.

### 7. Find the effective resistance and current \(I_T\) flowing in the given circuit (6 marks):
- To calculate the effective resistance \(R_T\) for a parallel circuit, use the formula:

  \[
  \frac{1}{R_T} = \frac{1}{R_1} + \frac{1}{R_2} + \frac{1}{R_3}
  \]
  After calculating \(R_T\), the total current \(I_T\) can be found using:

  \[
  I_T = \frac{V_T}{R_T}
  \]
  where \(V_T\) is the total voltage in the circuit.

---

Would you like detailed calculations for any specific part or help with clarifying any concepts? Here are some related questions:

1. What is the difference between resistance and conductance?
2. How does a parallel circuit affect total resistance compared to a series circuit?
3. How can Ohm’s Law be applied in AC circuits?
4. What are the practical advantages of using the power formula \(P = V^2/R\)?
5. How is conductance used in real-world electrical circuits?

**Tip**: In electrical circuits, parallel connections reduce the overall resistance, leading to an increase in total current drawn from the power source.

Answer questions on electrical quantities and circuit analysis as shown in the image. Topics include resistance, voltage, energy, power, conductance, charge, capacitance, Ohm's law, and power calculations.

This exercise covers key electrical concepts such as resistance, voltage, energy, and power. It includes applications of Ohm's Law, calculation of conductance, and determination of power in circuits. Learn how to analyze circuits with parallel connections and solve for current and resistance using key formulas.

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