Math Problem Statement

what is the domain and range

Solution

Let's determine the domain and range of the given piecewise function:

1. Domain:

The domain of a function is the set of all possible input values (x-values) for which the function is defined.

For the given piecewise function:

  • f(x)=x25f(x) = x^2 - 5 is defined for x0x \leq 0.
  • f(x)=2f(x) = 2 is defined for 0<x<30 < x < 3.
  • f(x)=x+1f(x) = x + 1 is defined for x3x \geq 3.

The function covers all values of xx from negative infinity to positive infinity without any gaps.

Domain: (,)(-\infty, \infty) or all real numbers R\mathbb{R}.

2. Range:

The range of a function is the set of all possible output values (y-values) that the function can take.

Let's analyze each part of the function to determine the range:

  • For x25x^2 - 5 when x0x \leq 0:

    • The minimum value occurs at x=0x = 0, giving f(0)=5f(0) = -5.
    • As xx decreases (becomes more negative), x2x^2 increases, so f(x)f(x) becomes more positive.
    • Thus, the range for this part is (5,)(-5, \infty).
  • For f(x)=2f(x) = 2 when 0<x<30 < x < 3:

    • The output is constantly 22, so the range for this part is just {2}\{2\}.
  • For f(x)=x+1f(x) = x + 1 when x3x \geq 3:

    • The smallest value occurs at x=3x = 3, giving f(3)=4f(3) = 4.
    • As xx increases, f(x)f(x) also increases.
    • Thus, the range for this part is [4,)[4, \infty).

Now, combining the ranges of each piece:

Range: The combined range is (5,2][4,)(-5, 2] \cup [4, \infty).

This indicates the function takes values starting from just above 5-5 up to 22, and then from 44 onward to infinity.

Do you want to delve into more details or have any questions?

Here are 5 related questions:

  1. How would the domain and range change if the interval for f(x)=x25f(x) = x^2 - 5 were expanded beyond x=0x = 0?
  2. Can you identify the points on the graph where the function is discontinuous?
  3. What would be the range if f(x)=2f(x) = 2 were extended to include x=3x = 3?
  4. How does changing the coefficient of xx in the linear part f(x)=x+1f(x) = x + 1 affect the range?
  5. What is the effect on the range if we alter the quadratic function to f(x)=(x2)+5f(x) = -(x^2) + 5 for x0x \leq 0?

Tip: To determine the range of a piecewise function, evaluate the output values (y-values) over each interval separately, and then combine the results.

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Math Problem Analysis

Mathematical Concepts

Functions
Piecewise Functions
Domain
Range

Formulas

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Theorems

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Suitable Grade Level

Grades 9-12