Math Problem Statement

f(x,y)=sqrt(9-x^2-y). Explain how to calculate the domain and range

Solution

To calculate the domain and range of the function f(x,y)=9x2yf(x, y) = \sqrt{9 - x^2 - y}, let's break it down step by step.

1. Domain:

The domain of a function refers to all possible input values (in this case, pairs (x,y)(x, y)) that make the function valid. For a square root function to be defined, the expression inside the square root must be non-negative because the square root of a negative number is not a real number.

So, for f(x,y)=9x2yf(x, y) = \sqrt{9 - x^2 - y} to be valid, the expression inside the square root must satisfy:

9x2y09 - x^2 - y \geq 0

Rearranging this inequality:

y9x2y \leq 9 - x^2

This inequality tells us the possible values for yy given any xx. So, for each xx, the corresponding yy must be less than or equal to 9x29 - x^2. The value of xx must also satisfy 3x3-3 \leq x \leq 3 because x29x^2 \leq 9.

Thus, the domain is all pairs (x,y)(x, y) such that:

3x3andy9x2-3 \leq x \leq 3 \quad \text{and} \quad y \leq 9 - x^2

2. Range:

The range of a function refers to all possible output values (the values of f(x,y)f(x, y)).

Since the function is a square root, the output of f(x,y)f(x, y) is always non-negative. Additionally, the value of the square root reaches its maximum when the expression inside the square root is maximized. The maximum value of 9x2y9 - x^2 - y occurs when x=0x = 0 and y=0y = 0, which gives:

f(0,0)=9020=9=3f(0, 0) = \sqrt{9 - 0^2 - 0} = \sqrt{9} = 3

Thus, the range of the function is:

[0,3][0, 3]

Summary:

  • The domain is all (x,y)(x, y) such that 3x3-3 \leq x \leq 3 and y9x2y \leq 9 - x^2.
  • The range is all real values f(x,y)[0,3]f(x, y) \in [0, 3].

Do you want further details on any part of this explanation? Here are five questions that build on this concept:

  1. How does the shape of the domain look in the xy-plane?
  2. What happens if the expression inside the square root is negative?
  3. Can the range of a square root function ever include negative values?
  4. How would the domain change if the function were f(x,y)=9x2y2f(x, y) = \sqrt{9 - x^2 - y^2}?
  5. Can we extend this reasoning to functions involving cube roots?

Tip: Always check the inside of the square root for non-negative values when calculating the domain of square root functions.

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Math Problem Analysis

Mathematical Concepts

Multivariable Functions
Square Root Functions
Domain and Range

Formulas

f(x, y) = sqrt(9 - x^2 - y)

Theorems

Non-negativity of Square Roots
Inequalities for Domain Restrictions

Suitable Grade Level

Grades 10-12