Based on the description of the graph, let's go step by step.

a. The Domain:

The domain of a function refers to all possible $x$-values for which the function is defined.

Since the parabola is a downward-opening curve and the graph shows that the parabola stretches infinitely in both the left and right directions, the domain will be all real numbers.

Thus, the domain is:

$\boxed{(-\infty, \infty)}$

b. The Range:

The range refers to all possible $y$-values that the function can take.

Since the parabola opens downward, the highest value of $y$ occurs at the vertex, which is $(0, 1)$. From there, the graph goes downward. Therefore, the $y$-values can be any value less than or equal to 1.

Thus, the range is:

$\boxed{(-\infty, 1]}$

c. The x-intercepts:

The x-intercepts occur where the graph crosses the x-axis. These are the points where $y = 0$.

From the given points, we know that the parabola crosses the x-axis at $x = -1$ and $x = 1$.

Thus, the x-intercepts are:

$\boxed{(-1, 0) \text{ and } (1, 0)}$

d. The y-intercept:

The y-intercept occurs where the graph crosses the y-axis, i.e., when $x = 0$.

From the given vertex, we know the graph passes through $(0, 1)$, so the y-intercept is:

$\boxed{(0, 1)}$

e. The missing function values:

We are asked to find the values of the function at $x = -2$ and $x = 2$.

From the graph, it is given that $f(-2) = -3$ and $f(2) = -3$.

Thus:

$f(-2) = -3 \quad \text{and} \quad f(2) = -3$

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If you have any further questions or would like more details on any part of the solution, feel free to ask!

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Related Questions:

1. How would you describe the symmetry of this parabola?
2. What are some key characteristics of quadratic functions?
3. How do you find the vertex of a parabola from its equation?
4. How do you determine whether a parabola opens upwards or downwards?
5. What is the general form of a quadratic equation?

Tip: When analyzing a parabola, always identify the vertex first—it gives you important clues about the maximum or minimum values and the axis of symmetry.