Math Problem Statement

Let f(x) = sqrt(x^2 - 9) and g(x) = 2/x. Determine the domain of f + g, f/g, and g(f(x)).

Solution

The problem in the image states the following:

  1. Let f(x)=x29f(x) = \sqrt{x^2 - 9} and g(x)=2xg(x) = \frac{2}{x}. Determine the domain.
    • a. f+gf + g
    • b. fg\frac{f}{g}
    • c. gfg \circ f, then determine the formula of gfg \circ f.

Let's analyze these functions and solve each part.

Step 1: Finding the domain of f(x)=x29f(x) = \sqrt{x^2 - 9}

The expression inside the square root must be non-negative: x290x^2 - 9 \geq 0 (x3)(x+3)0(x - 3)(x + 3) \geq 0 This inequality holds for x3x \leq -3 or x3x \geq 3. So, the domain of f(x)f(x) is: (,3][3,)(-\infty, -3] \cup [3, \infty)

Step 2: Finding the domain of g(x)=2xg(x) = \frac{2}{x}

The denominator must not be zero: x0x \neq 0 Thus, the domain of g(x)g(x) is: (,0)(0,)(-\infty, 0) \cup (0, \infty)

Part (a): Domain of f+gf + g

The domain of f+gf + g is the intersection of the domains of ff and gg: Domain of f+g=((,3][3,))((,0)(0,))\text{Domain of } f + g = ((-\infty, -3] \cup [3, \infty)) \cap ((-\infty, 0) \cup (0, \infty)) This results in: (,3][3,)(-\infty, -3] \cup [3, \infty)

Part (b): Domain of fg\frac{f}{g}

For the fraction fg\frac{f}{g} to be defined, both f(x)f(x) and g(x)g(x) must be defined, and g(x)0g(x) \neq 0. Since g(x)=2xg(x) = \frac{2}{x}, it is already clear that x0x \neq 0. The domain remains: (,3][3,)(-\infty, -3] \cup [3, \infty)

Part (c): Domain and formula of gfg \circ f

To find the domain of the composition gfg \circ f, we need f(x)f(x) to be in the domain of gg. Since g(x)=2xg(x) = \frac{2}{x}, we need f(x)0f(x) \neq 0. The values for f(x)f(x) must be positive or negative but not zero. Since f(x)=x29f(x) = \sqrt{x^2 - 9}, it only equals zero when x=±3x = \pm 3, which are the boundaries of its domain.

Thus, the domain of gfg \circ f remains: (,3][3,)(-\infty, -3] \cup [3, \infty)

The formula for gfg \circ f is: g(f(x))=2x29g(f(x)) = \frac{2}{\sqrt{x^2 - 9}}

Would you like more details or have any questions about these solutions?

Here are five related questions to deepen your understanding:

  1. What would be the domain if the function were f(x)=9x2f(x) = \sqrt{9 - x^2}?
  2. How do you solve quadratic inequalities in general?
  3. What happens to the domain of a composition fgf \circ g if g(x)g(x) has a smaller domain than f(x)f(x)?
  4. What are the general conditions for adding or dividing two functions in terms of their domains?
  5. How would the range of these functions affect their compositions?

Tip: When finding the domain of a composition of functions, always check that the output of the inner function lies within the domain of the outer function.

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Math Problem Analysis

Mathematical Concepts

Functions
Domain of functions
Composition of functions
Square root function
Rational functions

Formulas

f(x) = sqrt(x^2 - 9)
g(x) = 2/x
g(f(x)) = 2/sqrt(x^2 - 9)

Theorems

Domain of square root function
Domain of rational functions
Intersection of domains for function operations

Suitable Grade Level

Grades 10-12