Let the share of one son be $x$. Then, according to the problem:

• Widow's share = $2x$ (twice as much as one son)
• Daughter's share = $\frac{x}{2}$ (half of what one son receives)
• Two sons together receive $2x$ (equal shares for both sons).

The total property value is Rs. 180,000. The sum of the shares must equal this total:

$\text{Widow's share} + \text{Daughter's share} + \text{Two sons' shares} = 180,000$

Substitute the shares into the equation:

$2x + \frac{x}{2} + 2x = 180,000$

Step 1: Simplify the equation

Combine like terms:

$2x + 2x + \frac{x}{2} = 180,000$

$4x + \frac{x}{2} = 180,000$

Multiply through by 2 to eliminate the fraction:

$8x + x = 360,000$

$9x = 360,000$

Step 2: Solve for $x$

$x = \frac{360,000}{9} = 40,000$

Step 3: Calculate individual shares

• Each son receives $x = 40,000$.
• The widow receives $2x = 2 \times 40,000 = 80,000$.
• The daughter receives $\frac{x}{2} = \frac{40,000}{2} = 20,000$.

Thus, the shares are:

• Widow: Rs. 80,000
• Daughter: Rs. 20,000
• Each son: Rs. 40,000

Final Answer:

Option D: 40,000, 80,000, and 20,000

Would you like a detailed breakdown of the calculations or additional examples?

5 Related Questions:

1. How would the shares change if the daughter were to receive twice the share of one son?
2. What would happen if the widow's share was reduced to equal one son's share?
3. Can we divide the estate using percentages instead of specific rules?
4. How would the division look if there were three sons instead of two?
5. What is the total percentage each person receives from the estate?

Tip:

When dealing with word problems involving ratios, always translate relationships into algebraic equations systematically.