https://file.aiquickdraw.com/mathbot/file/1726157314983vlwnu46o.jpg

Let me help you with some of the problems I can read from the image:

1. **Problem 19**: "Determinați valoarea cifrei *x*, știind că numărul *50×6* se divide cu 3, dar nu și cu 9."

This is a divisibility rule problem. For a number to be divisible by 3, the sum of its digits must be divisible by 3. For it not to be divisible by 9, the sum of its digits should not be divisible by 9.

Given number: \( 50x6 \)

The sum of the digits is \( 5 + 0 + x + 6 = 11 + x \).

- For divisibility by 3: \( 11 + x \) must be divisible by 3.
- For not divisible by 9: \( 11 + x \) must **not** be divisible by 9.

Let’s solve this:

- \( 11 + x \equiv 0 \ (\text{mod} \ 3) \) means \( x \equiv 1 \ (\text{mod} \ 3) \).
  So, \( x = 1 \) or \( x = 4 \) or \( x = 7 \).

- Now check divisibility by 9 for \( 11 + x \). We need to ensure \( 11 + x \) is not divisible by 9.

For:
- \( x = 1 \): \( 11 + 1 = 12 \), which is divisible by 3 but **not** by 9.
- \( x = 4 \): \( 11 + 4 = 15 \), which is divisible by 3 but **not** by 9.
- \( x = 7 \): \( 11 + 7 = 18 \), which **is** divisible by 9.

Therefore, the possible values of \( x \) are **1** and **4**.

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2. **Problem 21**: "Aflați suma divizorilor naturali ai numărului 24."

The divisors of 24 are: \( 1, 2, 3, 4, 6, 8, 12, 24 \).

The sum is:
\[ 1 + 2 + 3 + 4 + 6 + 8 + 12 + 24 = 60. \]

So, the sum of the divisors is **60**.

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3. **Problem 22**: "Câți multipli ai numărului 15 sunt mai mari decât 300, dar mai mici decât 1000?"

We need to find the multiples of 15 in the range \( (300, 1000) \).

- First multiple of 15 greater than 300: \( 15 \times 21 = 315 \).
- Largest multiple of 15 less than 1000: \( 15 \times 66 = 990 \).

Now, the multiples are: \( 315, 330, 345, \dots, 990 \).

This forms an arithmetic progression with the first term \( a = 315 \), common difference \( d = 15 \), and last term \( l = 990 \).

The number of terms is:
\[
n = \frac{l - a}{d} + 1 = \frac{990 - 315}{15} + 1 = 46.
\]

So, there are **46 multiples** of 15 between 300 and 1000.

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Would you like me to provide details on any of these problems or further explain any concepts?

Here are 5 related questions based on these problems:
1. How do we determine divisibility by numbers other than 3 and 9?
2. What is the general method to find the sum of divisors for a number like 36 or 48?
3. How can you determine the greatest common divisor of two numbers?
4. How would you solve a similar problem to find multiples of a number like 25 between certain limits?
5. What is the rule to determine if a number is divisible by both 6 and 9?

**Tip:** When checking divisibility by 3 or 9, always sum the digits of the number for a quick check!

Determinați valoarea cifrei x, știind că numărul 50x6 se divide cu 3, dar nu și cu 9. Aflați suma divizorilor naturali ai numărului 24. Câți multipli ai numărului 15 sunt mai mari decât 300, dar mai mici decât 1000?

Explore three important math problems: finding digits for divisibility, summing divisors, and counting multiples in a range. These exercises cover core number theory concepts for students in Grades 5-8.

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