Math Problem Statement

William is making pies with the fresh peaches he picked at Butterscotch Orchard. He prepares the peaches by chopping them into small pieces. William has a total of 1 7 8 pounds of peaches for his pies. He makes 3 pies, each with the same amount of peaches. How many pounds of peaches are in each pie? Use the model to help answer the question.

Solution

To determine how many pounds of peaches William uses for each pie, we need to divide the total amount of peaches by the number of pies. William has 1781 \frac{7}{8} pounds of peaches in total, and he makes 3 pies. Let's break this problem into steps:

Step 1: Convert the mixed number to an improper fraction.

The total weight of peaches is given as 1781 \frac{7}{8} pounds. To convert this mixed number to an improper fraction: 178=8×1+78=1581 \frac{7}{8} = \frac{8 \times 1 + 7}{8} = \frac{15}{8}

Step 2: Divide the total weight by 3 pies.

Now, we need to divide the total weight of peaches by 3: 158÷3=158×13=1524\frac{15}{8} \div 3 = \frac{15}{8} \times \frac{1}{3} = \frac{15}{24}

Step 3: Simplify the fraction.

Simplify 1524\frac{15}{24} by dividing both the numerator and the denominator by their greatest common divisor, which is 3: 1524=58\frac{15}{24} = \frac{5}{8}

So, each pie contains 58\frac{5}{8} pounds of peaches.

Would you like further details or explanations?

Here are 5 related questions:

  1. How would you divide peaches if the weight was given as a decimal instead of a fraction?
  2. How can you convert improper fractions back to mixed numbers?
  3. What if William wanted to make 4 pies instead of 3? How much would be in each pie?
  4. How do you add or subtract mixed numbers in other pie-making scenarios?
  5. How do you find the greatest common divisor for fraction simplifications?

Tip: Always simplify fractions by finding the greatest common divisor to make calculations easier.

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Math Problem Analysis

Mathematical Concepts

Fractions
Division of Fractions
Simplification

Formulas

Improper fraction conversion
Division of fractions
Simplification of fractions

Theorems

Greatest Common Divisor for Fraction Simplification

Suitable Grade Level

Grades 4-6