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The problem asks us to divide \( \frac{2}{3} \) by \( \left(-\frac{1}{4}\right) \).

To divide by a fraction, you multiply by its reciprocal. Therefore, this operation becomes:

\[
\frac{2}{3} \div \left(-\frac{1}{4}\right) = \frac{2}{3} \times \left(-4\right)
\]

Now, multiplying:

\[
\frac{2}{3} \times \left(-4\right) = \frac{2 \times -4}{3} = \frac{-8}{3}
\]

So, the answer is \( \frac{-8}{3} \).

Would you like further details or have any questions? Here are some related questions:

1. How do you convert division of fractions into multiplication?
2. What is the reciprocal of a fraction, and how is it used?
3. How would this problem change if the second fraction was positive instead of negative?
4. Can you simplify \( \frac{-8}{3} \) to a mixed number?
5. What are some examples of dividing fractions by whole numbers?

**Tip:** When dividing fractions, always remember to multiply by the reciprocal of the divisor!

Divide \( \frac{2}{3} \) by \( \left(-\frac{1}{4}\right) \).

Learn how to solve the division of fractions problem \( \frac{2}{3} \div \left(-\frac{1}{4}\right) \) by multiplying by the reciprocal. This example is suitable for students in Grades 6-8, covering key concepts such as fraction division and reciprocal multiplication.

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