Math Problem Statement
Help solve
Solution
Let's go through the problems one by one, and I'll help solve them using the distributive property.
Problem 1:
Using the distributive property: So, the solution is .
Problem 2:
The answer is .
Problem 3:
So, the answer is .
Problem 4:
Distribute : The answer is .
Problem 5:
Using the distributive property: So, the answer is .
Problem 6:
First, apply the distributive property to : Now add 23: The answer is .
Problem 7: Double the expression
To double the expression, multiply everything by 2: So, the answer is .
Problem 8:
First, apply the distributive property: Now subtract 2: The answer is .
Problem 9:
Using the distributive property: So, the answer is .
Problem 10:
First, apply the distributive property: Now subtract from 6: The answer is .
Problem 11: If the length of a square is , what is the perimeter?
The perimeter of a square is 4 times the length of one side. The side length is , or . So, the perimeter is .
Feel free to ask for further clarification! Here are five related questions:
- How does the distributive property work for both addition and subtraction?
- How can you simplify expressions involving fractions and the distributive property?
- How does multiplying a binomial affect each term inside parentheses?
- What is the importance of correctly distributing negative signs across terms?
- How do you find the perimeter of a rectangle or square in terms of algebraic expressions?
Tip: When using the distributive property, always ensure each term inside the parentheses is multiplied by the factor outside.
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Math Problem Analysis
Mathematical Concepts
Algebra
Distributive Property
Simplifying Expressions
Formulas
Distributive Property: a(b + c) = ab + ac
Perimeter of a square: P = 4 × side
Theorems
Distributive Property
Suitable Grade Level
Grades 6-8
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