It looks like you are referring to points \( P(-3, 5) \) and \( Q(7, 0) \). There are several possible questions related to these points, such as finding the distance between the points, the slope of the line through the points, the equation of the line, or something else.

Here are some common calculations:

### 1. Distance between points \( P \) and \( Q \):
The distance formula between two points \( P(x_1, y_1) \) and \( Q(x_2, y_2) \) is:
\[
d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}
\]
Substituting the given coordinates \( P(-3, 5) \) and \( Q(7, 0) \):
\[
d = \sqrt{(7 - (-3))^2 + (0 - 5)^2} = \sqrt{(7 + 3)^2 + (-5)^2} = \sqrt{10^2 + (-5)^2} = \sqrt{100 + 25} = \sqrt{125} = 5\sqrt{5}
\]
So, the distance between points \( P \) and \( Q \) is \( 5\sqrt{5} \).

### 2. Slope of the line passing through \( P \) and \( Q \):
The slope \( m \) between two points \( P(x_1, y_1) \) and \( Q(x_2, y_2) \) is given by:
\[
m = \frac{y_2 - y_1}{x_2 - x_1}
\]
Substituting the coordinates \( P(-3, 5) \) and \( Q(7, 0) \):
\[
m = \frac{0 - 5}{7 - (-3)} = \frac{-5}{7 + 3} = \frac{-5}{10} = -\frac{1}{2}
\]
So, the slope of the line is \( -\frac{1}{2} \).

Would you like more details or have any questions?

Here are 5 related questions:
1. What is the midpoint of the segment joining \( P \) and \( Q \)?
2. What is the equation of the line passing through \( P \) and \( Q \)?
3. How would you calculate the angle that the line between \( P \) and \( Q \) makes with the x-axis?
4. What are the intercepts of the line passing through \( P \) and \( Q \)?
5. How can you verify if another point \( R \) lies on the line through \( P \) and \( Q \)?

**Tip:** The slope tells us how steep a line is. A negative slope means the line is decreasing as you move from left to right!

Learn how to calculate the distance and slope between points P(-3, 5) and Q(7, 0) using the distance formula and slope formula. This problem explores coordinate geometry concepts and is suitable for students in Grades 9-11.

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