A model airplane has a position function given by i (t) = (-343 + 10t2 + 100t) + (-001t* - 4.912 +
25t)3. What is the airplane's displacement (in meters) from t = 1 s to t = 4 s?

The given position function of the model airplane is expressed as:

\[
\mathbf{i}(t) = (-343 + 10t^2 + 100t)\hat{i} + (-0.001t^3 - 4.912 + 25t)\hat{j}
\]

This is a vector function describing the position of the airplane at any time \( t \), where the \( \hat{i} \) and \( \hat{j} \) components represent the x and y coordinates, respectively.

To find the airplane's displacement from \( t = 1 \, \text{s} \) to \( t = 4 \, \text{s} \), we will follow these steps:

### Step 1: Find the position at \( t = 1 \, \text{s} \)
Substitute \( t = 1 \) into both the \( \hat{i} \)-component and the \( \hat{j} \)-component of the position function.

For \( \hat{i} \)-component:
\[
\mathbf{i}(1)_{\hat{i}} = -343 + 10(1)^2 + 100(1) = -343 + 10 + 100 = -233
\]

For \( \hat{j} \)-component:
\[
\mathbf{i}(1)_{\hat{j}} = -0.001(1)^3 - 4.912 + 25(1) = -0.001 - 4.912 + 25 = 20.087
\]

Thus, the position at \( t = 1 \, \text{s} \) is:
\[
\mathbf{i}(1) = (-233, 20.087)
\]

### Step 2: Find the position at \( t = 4 \, \text{s} \)
Substitute \( t = 4 \) into both the \( \hat{i} \)-component and the \( \hat{j} \)-component of the position function.

For \( \hat{i} \)-component:
\[
\mathbf{i}(4)_{\hat{i}} = -343 + 10(4)^2 + 100(4) = -343 + 10(16) + 400 = -343 + 160 + 400 = 217
\]

For \( \hat{j} \)-component:
\[
\mathbf{i}(4)_{\hat{j}} = -0.001(4)^3 - 4.912 + 25(4) = -0.001(64) - 4.912 + 100 = -0.064 - 4.912 + 100 = 95.024
\]

Thus, the position at \( t = 4 \, \text{s} \) is:
\[
\mathbf{i}(4) = (217, 95.024)
\]

### Step 3: Calculate the displacement
The displacement is the difference between the positions at \( t = 4 \, \text{s} \) and \( t = 1 \, \text{s} \).

For the \( \hat{i} \)-component:
\[
\Delta x = 217 - (-233) = 217 + 233 = 450
\]

For the \( \hat{j} \)-component:
\[
\Delta y = 95.024 - 20.087 = 74.937
\]

Thus, the displacement vector is:
\[
\Delta \mathbf{i} = (450, 74.937)
\]

### Step 4: Calculate the magnitude of the displacement
The magnitude of the displacement vector is given by the formula:
\[
|\Delta \mathbf{i}| = \sqrt{(\Delta x)^2 + (\Delta y)^2}
\]
Substituting the values:
\[
|\Delta \mathbf{i}| = \sqrt{(450)^2 + (74.937)^2} = \sqrt{202500 + 5615.31} = \sqrt{208115.31} \approx 456.13 \, \text{m}
\]

Thus, the displacement of the airplane from \( t = 1 \, \text{s} \) to \( t = 4 \, \text{s} \) is approximately \( 456.13 \, \text{m} \).

---

Would you like more details on any step?

### Related Questions:
1. How do you compute velocity from a position function?
2. What is the significance of the direction of the displacement vector?
3. How do you differentiate between displacement and distance?
4. How would acceleration be calculated from this position function?
5. What role do the components \( \hat{i} \) and \( \hat{j} \) play in vector functions?

### Tip:
Always check if the components of your vector function involve time-dependent variables to avoid computational mistakes when finding positions or displacement over time.

A model airplane has a position function given by i(t) = (-343 + 10t^2 + 100t) + (-0.001t^3 - 4.912 + 25t). What is the airplane's displacement (in meters) from t = 1 s to t = 4 s?

Learn how to calculate the displacement of a model airplane using its position function over time. This example covers vector calculus concepts, including the displacement formula and magnitude calculation using the Pythagorean theorem. Suitable for students in Grade 11-12 or early college physics/calculus courses.

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