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The problem asks to write a direct variation equation to find the number of miles a jet travels in 3 hours if it is flying at a rate of 600 mph.

A direct variation equation follows the form \( y = kx \), where \( y \) is the distance, \( k \) is the constant rate (speed), and \( x \) is the time. In this case:

- The speed of the jet, \( k \), is 600 mph.
- The time, \( x \), is 3 hours.

Thus, the equation should look like:

\[
y = 600x
\]

where \( y \) represents the number of miles traveled in \( x \) hours.

The correct choice from the options in the image would be:
- \( y = 600 \times 3 \)

Would you like more details or have any questions?

Here are some related questions to further your understanding:
1. What is direct variation, and how is it applied in real-life scenarios?
2. How do you solve for time if you know the distance and speed?
3. What other types of equations describe motion, such as when acceleration is involved?
4. How would the equation change if the speed was given in kilometers per hour?
5. Can this equation be used to calculate the distance for any speed and time?

**Tip:** Direct variation always assumes a constant rate. Make sure the rate remains unchanged throughout the problem.

Write a direct variation equation to find the number of miles a jet travels in 3 hours if it is flying at a rate of 600 mph.

Learn how to write a direct variation equation to calculate the distance traveled by a jet in 3 hours at a constant speed of 600 mph. This problem is suitable for students in Grades 6-8 and covers key algebra concepts such as direct variation and linear equations.

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