Math Problem Statement

The area A of a square varies directly as the square of its side 5

Solution

In this problem, the area AA of a square varies directly as the square of its side length ss. This means we can express this relationship using the equation:

A=ks2A = k s^2

Where:

  • AA is the area of the square,
  • ss is the side length,
  • kk is a constant of proportionality.

Now, according to the problem, the side length is 5 units. We can substitute s=5s = 5 into the equation:

A=k×52A = k \times 5^2 A=25kA = 25k

Without more information about the value of AA, we cannot determine the value of kk directly, but the relationship A=25kA = 25k holds true as a formula. If you know the area AA, you can solve for kk and find the specific area of the square.

Would you like to explore further details or another example with specific values?

Here are five questions to deepen the concept:

  1. What is the constant kk if the area of the square is 100 square units?
  2. How would the formula change if the side length of the square doubled?
  3. Can you express the relationship between the side length and the area in terms of a ratio?
  4. What happens to the area if the side length is tripled?
  5. How would the concept of "varying directly" differ if this were a rectangle instead of a square?

Tip: When a variable "varies directly" with another, it means any increase in one variable causes a proportional increase in the other.

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Math Problem Analysis

Mathematical Concepts

Direct Variation
Geometry
Area of a Square

Formulas

A = k * s^2 (Direct Variation Formula)
A = s^2 (Area of a Square)

Theorems

Direct Proportionality Theorem

Suitable Grade Level

Grades 6-8