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To solve this question, we need to determine the possible digits in the ones place of prime numbers greater than 10.

### Prime Numbers Recap:
1. **Prime numbers** are integers greater than 1 that have no divisors other than 1 and themselves.
2. For prime numbers greater than 10, they **cannot end in an even digit (0, 2, 4, 6, 8)** or in 5, because such numbers would be divisible by 2 or 5.

### Analyzing the Digits:
- **0**: Not possible because any number ending in 0 is divisible by 10.
- **2**: Not possible because any number ending in 2 is divisible by 2.
- **3**: Possible. For example, 13, 23, 43, etc., are primes ending in 3.
- **7**: Possible. For example, 17, 37, 67, etc., are primes ending in 7.
- **9**: Not possible because any number ending in 9 is divisible by 3.

### Final Answer:
The digits **3** and **7** might be in the ones place of prime numbers greater than 10. 

Let me know if you'd like further clarification or additional examples! Here are five related questions to explore:

1. Why can't prime numbers greater than 10 end in 0 or 5?
2. How many prime numbers less than 50 end in the digit 3?
3. What is the largest prime number less than 100 that ends in the digit 7?
4. Are there any rules to quickly check if a number is prime?
5. Can a prime number end in 1? Why or why not?

**Tip:** To check for primes efficiently, use divisibility rules or a prime sieve (e.g., Sieve of Eratosthenes) for numbers up to a certain limit.

Which of the following digits might prime numbers greater than 10 have in the ones place? Select all that apply.

Discover which digits prime numbers greater than 10 can have in the ones place. This question explores key mathematical concepts such as prime numbers, divisibility rules, and why certain digits like 0 or 5 are not possible. Ideal for students in Grades 6-8.

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