Math Problem Statement

Differentiate. yequalslog Subscript 5 Baseline x Question content area bottom Part 1 StartFraction d Over dx EndFraction log Subscript 5 Baseline xequals    enter your response here

Solution

To differentiate y=log5xy = \log_5 x with respect to xx, we can use the following derivative rule for logarithms:

ddxlogbx=1xlnb\frac{d}{dx} \log_b x = \frac{1}{x \ln b}

where bb is the base of the logarithm.

Here, b=5b = 5, so the derivative of log5x\log_5 x is:

ddxlog5x=1xln5\frac{d}{dx} \log_5 x = \frac{1}{x \ln 5}

This is the derivative of y=log5xy = \log_5 x with respect to xx.

Would you like further clarification or details? Here are 5 related questions that may help expand on this topic:

  1. How do you differentiate logarithmic functions with other bases?
  2. What is the derivative of natural logarithms lnx\ln x?
  3. How does the change of base formula for logarithms work in differentiation?
  4. Can you apply the chain rule to differentiate more complex logarithmic functions?
  5. How do logarithmic derivatives relate to exponential functions?

Tip: When differentiating logarithms with any base, converting to natural logs often simplifies the process.

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Math Problem Analysis

Mathematical Concepts

Calculus
Logarithmic Functions
Differentiation

Formulas

\frac{d}{dx} \log_b x = \frac{1}{x \ln b}

Theorems

Logarithmic differentiation rule

Suitable Grade Level

Grades 11-12