Math Problem Statement

Let f(x)=xe^x\cos(x). Find f' \left( \frac{\pi}{6} \right). Please enter your answer in decimal form with three digits after the decimal point.

Solution

To find f(π6)f' \left( \frac{\pi}{6} \right) for the function f(x)=xexcos(x)f(x) = x e^x \cos(x), we'll follow these steps:

Step 1: Differentiate f(x)f(x)

The function is a product of three terms: xx, exe^x, and cos(x)\cos(x). To differentiate this, we will apply the product rule, which states:

(fg)=fg+fg(fg)' = f'g + fg'

For three functions u(x),v(x),w(x)u(x), v(x), w(x), the product rule is extended as:

ddx[u(x)v(x)w(x)]=u(x)v(x)w(x)+u(x)v(x)w(x)+u(x)v(x)w(x)\frac{d}{dx}[u(x)v(x)w(x)] = u'(x)v(x)w(x) + u(x)v'(x)w(x) + u(x)v(x)w'(x)

Here:

  • u(x)=xu(x) = x
  • v(x)=exv(x) = e^x
  • w(x)=cos(x)w(x) = \cos(x)

Now, we calculate each derivative:

  • u(x)=1u'(x) = 1
  • v(x)=exv'(x) = e^x
  • w(x)=sin(x)w'(x) = -\sin(x)

Using the product rule:

f(x)=(1)(excos(x))+(x)(excos(x))+(x)(ex(sin(x)))f'(x) = (1)(e^x \cos(x)) + (x)(e^x \cos(x)) + (x)(e^x (-\sin(x))) f(x)=excos(x)+xexcos(x)xexsin(x)f'(x) = e^x \cos(x) + x e^x \cos(x) - x e^x \sin(x)

Step 2: Substitute x=π6x = \frac{\pi}{6}

Now, substitute x=π6x = \frac{\pi}{6} into the derivative:

f(π6)=eπ6cos(π6)+π6eπ6cos(π6)π6eπ6sin(π6)f' \left( \frac{\pi}{6} \right) = e^{\frac{\pi}{6}} \cos \left( \frac{\pi}{6} \right) + \frac{\pi}{6} e^{\frac{\pi}{6}} \cos \left( \frac{\pi}{6} \right) - \frac{\pi}{6} e^{\frac{\pi}{6}} \sin \left( \frac{\pi}{6} \right)

We know the following trigonometric values:

cos(π6)=32,sin(π6)=12\cos \left( \frac{\pi}{6} \right) = \frac{\sqrt{3}}{2}, \quad \sin \left( \frac{\pi}{6} \right) = \frac{1}{2}

Substitute these into the expression:

f(π6)=eπ632+π6eπ632π6eπ612f' \left( \frac{\pi}{6} \right) = e^{\frac{\pi}{6}} \cdot \frac{\sqrt{3}}{2} + \frac{\pi}{6} \cdot e^{\frac{\pi}{6}} \cdot \frac{\sqrt{3}}{2} - \frac{\pi}{6} \cdot e^{\frac{\pi}{6}} \cdot \frac{1}{2}

Step 3: Simplify and Calculate

Let's now calculate the values. I will compute the expression numerically.

The value of f(π6)f' \left( \frac{\pi}{6} \right) is approximately 1.7851.785, rounded to three decimal places.

Would you like further details or have any questions?

Here are some related questions to explore:

  1. How is the product rule applied in differentiation?
  2. How can we differentiate functions with more than two factors?
  3. What is the chain rule, and how does it compare to the product rule?
  4. How do you approximate the values of exponential and trigonometric functions?
  5. What are some common applications of derivatives in physics?

Tip: When differentiating multiple products, keep track of each term carefully to avoid errors in the final expression!

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Math Problem Analysis

Mathematical Concepts

Differentiation
Product Rule
Exponential Functions
Trigonometric Functions

Formulas

Product rule: (uv)' = u'v + uv'
Derivative of e^x: d/dx (e^x) = e^x
Derivative of cos(x): d/dx (cos(x)) = -sin(x)

Theorems

Product Rule of Differentiation

Suitable Grade Level

Grades 11-12