Math Problem Statement

solve

Differentiate y = (3x) / (e^x).

Solution

The image shows the function y=3xexy = \frac{3x}{e^x}, and the task is to differentiate it.

To differentiate the function y=3xexy = \frac{3x}{e^x}, we will apply the quotient rule, which is:

(f(x)g(x))=f(x)g(x)f(x)g(x)(g(x))2\left( \frac{f(x)}{g(x)} \right)' = \frac{f'(x)g(x) - f(x)g'(x)}{(g(x))^2}

Here, f(x)=3xf(x) = 3x and g(x)=exg(x) = e^x.

  1. Differentiate f(x)=3xf(x) = 3x: f(x)=3f'(x) = 3

  2. Differentiate g(x)=exg(x) = e^x: g(x)=exg'(x) = e^x

Now, applying the quotient rule:

y=(3)(ex)(3x)(ex)(ex)2y' = \frac{(3)(e^x) - (3x)(e^x)}{(e^x)^2}

Simplify the numerator:

y=3ex3xexe2xy' = \frac{3e^x - 3xe^x}{e^{2x}}

Factor out 3ex3e^x from the numerator:

y=3ex(1x)e2xy' = \frac{3e^x(1 - x)}{e^{2x}}

Finally, simplify the expression:

y=3(1x)exy' = \frac{3(1 - x)}{e^x}

Thus, the derivative is:

y=3(1x)exy' = \frac{3(1 - x)}{e^x}

Would you like more details on any of these steps?

Here are five related questions to explore:

  1. How does the quotient rule apply in other cases?
  2. What is the significance of the exponential function exe^x in calculus?
  3. Can the product rule be used in this scenario, and how would it compare?
  4. How can we differentiate other types of rational functions?
  5. What is the derivative of exe^x with other constants?

Tip: Always check if the function is best suited for the quotient rule or if it can be simplified first.

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Math Problem Analysis

Mathematical Concepts

Differentiation
Quotient Rule
Exponential Functions

Formulas

Quotient Rule: (f(x)/g(x))' = (f'(x)g(x) - f(x)g'(x)) / (g(x))^2
Derivative of e^x: (e^x)' = e^x

Theorems

Quotient Rule
Exponential Derivative Rule

Suitable Grade Level

Grades 11-12 (or early college calculus)