Math Problem Statement
Solution
To show that is in the span of , we need to express as a linear combination of and . In other words, we are looking for scalars and such that:
Given vectors:
Substituting the linear combination, we have:
Expanding this equation leads to a system of linear equations:
2 = 2a - b \\ 5 = -a + 2b \\ 8 = 0a + 2b \\ 3 = 5a - 3b \end{cases}$$ Solving this system will allow us to find values of $$a$$ and $$b$$ (if they exist) to confirm that $$\vec{x}$$ is in the span of $$\{\vec{y}, \vec{z}\}$$. ### Solving the System 1. From the third equation, $$8 = 2b$$, we can solve for $$b$$: $$b = \frac{8}{2} = 4$$ 2. Substitute $$b = 4$$ into the first equation: $$2 = 2a - 4 \Rightarrow 2a = 6 \Rightarrow a = 3$$ 3. Substitute $$a = 3$$ and $$b = 4$$ into the remaining equations to verify consistency. - Second equation: $$5 = -3 + 2 \cdot 4 = 5 \quad \text{(True)}$$ - Fourth equation: $$3 = 5 \cdot 3 - 3 \cdot 4 = 3 \quad \text{(True)}$$ ### Conclusion The values $$a = 3$$ and $$b = 4$$ satisfy all four equations, so: $$\vec{x} = 3\vec{y} + 4\vec{z}$$ Thus, $$\vec{x}$$ is indeed in the span of $$\{\vec{y}, \vec{z}\}$$. Would you like further details on any part of the solution? --- ### Related Questions 1. What is the span of a set of vectors, and why is it important in linear algebra? 2. How can we determine if a vector is linearly dependent on other vectors? 3. How would the solution change if one of the components of $$\vec{x}$$, $$\vec{y}$$, or $$\vec{z}$$ were different? 4. Can we use matrix methods (like Gaussian elimination) to solve the system instead? 5. How do the concepts of basis and dimension relate to vector spans? ### Tip When checking if a vector is in the span of others, setting up and solving a system of linear equations is often the most efficient approach.Ask a new question for Free
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Math Problem Analysis
Mathematical Concepts
Linear Algebra
Vector Spaces
Span
Linear Combination
Formulas
\(\vec{x} = a\vec{y} + b\vec{z}\)
Theorems
Linear Combination
Span Definition
Suitable Grade Level
College (Introductory Linear Algebra)
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