Math Problem Statement

A translation 5 units right and 3 units down, then a reflection across x=0 is applied to the point (5, -1). Where is the image in the coordinate system?

Solution

Let's solve this step-by-step.

  1. Initial Point: The initial point is (5,1)(5, -1).

  2. Translation:

    • Moving 5 units to the right adds 5 to the xx-coordinate: 5+5=105 + 5 = 10.
    • Moving 3 units down subtracts 3 from the yy-coordinate: 13=4-1 - 3 = -4.
    • The new point after translation is (10,4)(10, -4).
  3. Reflection:

    • Reflecting across the line x=0x = 0 (the yy-axis) changes the sign of the xx-coordinate but leaves the yy-coordinate the same.
    • So, the reflection of (10,4)(10, -4) across x=0x = 0 is (10,4)(-10, -4).
  4. Quadrant Identification:

    • The point (10,4)(-10, -4) lies in Quadrant III (where both xx and yy are negative).

Answer: The correct answer is C. Quadrant III.

Would you like more details on any of the steps?


Here are 5 related questions to expand your understanding:

  1. What would happen if the reflection was applied across the yy-axis instead?
  2. How would you translate a point by a different combination of units?
  3. How can we reflect a point across the line y=xy = x?
  4. What is the effect of reflecting a point across both the xx-axis and yy-axis?
  5. How can we determine the quadrant of a point based on its coordinates?

Tip: Remember that reflecting across the line x=0x = 0 simply changes the sign of the xx-coordinate, while reflecting across y=0y = 0 changes the sign of the yy-coordinate.

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Math Problem Analysis

Mathematical Concepts

Coordinate Geometry
Translations
Reflections
Quadrants

Formulas

Translation: (x + a, y + b)
Reflection over x = 0: (-x, y)

Theorems

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Suitable Grade Level

Grades 8-10