A 49V2+ ion has _ protons, _ neutrons, _ electrons

To determine the number of protons, neutrons, and electrons for a \(\text{V}^{2+}\) ion with a mass number of 49, follow these steps:

1. **Protons:** The atomic number of vanadium (V) is 23, which means that the ion has 23 protons.

2. **Neutrons:** The number of neutrons is found by subtracting the atomic number from the mass number. For this ion:
   \[
   49 - 23 = 26 \text{ neutrons}
   \]

3. **Electrons:** A \(\text{V}^{2+}\) ion has lost 2 electrons compared to a neutral vanadium atom. A neutral vanadium atom has 23 electrons (equal to the number of protons). Therefore, the \(\text{V}^{2+}\) ion has:
   \[
   23 - 2 = 21 \text{ electrons}
   \]

Thus, a \(\text{V}^{2+}\) ion with a mass number of 49 has **23 protons, 26 neutrons, and 21 electrons**.

Would you like more details or have any questions?

Here are some related questions to consider:

1. How would the number of electrons change if the ion was \(\text{V}^{3+}\) instead of \(\text{V}^{2+}\)?
2. What would be the number of neutrons in a \(\text{V}^{2+}\) ion with a mass number of 51?
3. How does the charge of an ion affect its chemical properties?
4. What is the electron configuration for a \(\text{V}^{2+}\) ion?
5. How would you determine the number of neutrons if only the atomic number and mass number were given?

**Tip:** For any ion, the charge indicates how many electrons have been lost or gained compared to the neutral atom. Subtract the ion's charge from the number of protons to determine the number of electrons in the ion.

Understand how to calculate the number of protons, neutrons, and electrons in a V^2+ ion with a mass number of 49. This problem involves atomic structure and ion chemistry, illustrating how charges affect electron counts.

Math Problem Statement

Solution

Ask a new question for Free

By Image

Math Problem Analysis

Mathematical Concepts

Formulas

Theorems

Suitable Grade Level

Related Recommendation