Determine the order of the following matrix:

open square bracket,

begin matrix

row 1, column 1, 2

row 1, column 2, minus, 5

row 1, column 3, 0

row 1, column 4, 2

row 2, column 1, 7

row 2, column 2, 6

row 2, column 3, 3

row 2, column 4, 0

end matrix

, close square bracket

To determine the order of a matrix, we need to identify the number of rows and columns in the matrix.

Here is the matrix as described:

\[
\begin{pmatrix}
2 & -5 & 0 & 2 \\
7 & 6 & 3 & 0
\end{pmatrix}
\]

This matrix has:

- **2 rows** (horizontal arrays of numbers)
- **4 columns** (vertical arrays of numbers)

Thus, the order of the matrix is **2 × 4**.

Would you like details or have any questions?

Here are five related questions:
1. What is the definition of a square matrix?
2. How do you find the determinant of a 2 × 2 matrix?
3. What is the difference between a row matrix and a column matrix?
4. Can a matrix have more columns than rows? If so, what is it called?
5. How is matrix multiplication defined for non-square matrices?

**Tip:** The order of a matrix is always given as "rows × columns," not the reverse!

Learn how to determine the order of a matrix with this detailed explanation. Understand the structure of the matrix and how to count rows and columns effectively. Suitable for high school students studying matrices and linear algebra.

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